01. Faraday's Law
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ELECTROCHEMISTRY

276084 One faraday of current was passed through the electrolytic cells placed in series containing solution of $\mathrm{Ag}^{+}, \mathrm{Ni}^{2+}$ and $\mathrm{Cr}^{3+}$ respectively. The ratio of amounts of $\mathrm{Ag}, \mathrm{Ni}$ and $\mathrm{Cr}$ deposited will be
(At. wt. of $\mathrm{Ag}=108, \mathrm{Ni}=59, \mathrm{Cr}=52$ )

1 $108: 29.5: 17.3$
2 $17.4: 29.5: 108$
3 $1: 2: 3$
4 $108: 59: 52$
ELECTROCHEMISTRY

276020 How many gram of cobalt metal will be deposited, when a solution of cobalt(II) chloride is electrolyzed with a current of 10 amperes for 109 minutes (1 Faraday $=96,500$ $\mathrm{C}$; Atomic mass of $\mathrm{Co}=\mathbf{5 9} \mathrm{u})$

1 4.0
2 20.0
3 40.0
4 0.66
ELECTROCHEMISTRY

275993 Given below are half cell reactions
$\mathrm{MnO}_{4}^{-}+8 \mathrm{H}^{+}+5 \mathrm{e}^{-} \rightarrow \mathrm{Mn}^{2+}+4 \mathrm{H}_{2} \mathrm{O}$
$\mathrm{E}_{\mathrm{Mn}^{2+} / \mathrm{MnO}_{4}^{-}}^{0}=-1.510 \mathrm{~V}$
$\frac{1}{2} \mathrm{O}_{2}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_{2} \mathrm{O}$
$\mathrm{E}_{\mathrm{O}_{2} / \mathrm{H}_{2} \mathrm{O}}^{\mathrm{0}}=1.223 \mathrm{~V}$
Will the permanganate ion, $\mathrm{MnO}_{4}^{-}$liberate $\mathrm{O}_{2}$ from water in the presence of an acid?

1 No, because $\mathrm{E}_{\text {cell }}^{\mathrm{o}}=-2.733 \mathrm{~V}$
2 Yes, because $\mathrm{E}_{\text {cell }}^{\mathrm{o}}=+0.287 \mathrm{~V}$
3 No, because $\mathrm{E}_{\text {cell }}^{\mathrm{o}}=-0.287 \mathrm{~V}$
4 Yes, because $\mathrm{E}_{\text {cell }}^{\mathrm{o}}=+2.733 \mathrm{~V}$
ELECTROCHEMISTRY

276021 When 965 coulombs of electricity is passed through a solution of silver nitrate, the amount of silver deposited is

1 $10.8 \mathrm{~g}$
2 $2.16 \mathrm{~g}$
3 $1.08 \mathrm{~g}$
4 $0.54 \mathrm{~g}$
ELECTROCHEMISTRY

276084 One faraday of current was passed through the electrolytic cells placed in series containing solution of $\mathrm{Ag}^{+}, \mathrm{Ni}^{2+}$ and $\mathrm{Cr}^{3+}$ respectively. The ratio of amounts of $\mathrm{Ag}, \mathrm{Ni}$ and $\mathrm{Cr}$ deposited will be
(At. wt. of $\mathrm{Ag}=108, \mathrm{Ni}=59, \mathrm{Cr}=52$ )

1 $108: 29.5: 17.3$
2 $17.4: 29.5: 108$
3 $1: 2: 3$
4 $108: 59: 52$
ELECTROCHEMISTRY

276020 How many gram of cobalt metal will be deposited, when a solution of cobalt(II) chloride is electrolyzed with a current of 10 amperes for 109 minutes (1 Faraday $=96,500$ $\mathrm{C}$; Atomic mass of $\mathrm{Co}=\mathbf{5 9} \mathrm{u})$

1 4.0
2 20.0
3 40.0
4 0.66
ELECTROCHEMISTRY

275993 Given below are half cell reactions
$\mathrm{MnO}_{4}^{-}+8 \mathrm{H}^{+}+5 \mathrm{e}^{-} \rightarrow \mathrm{Mn}^{2+}+4 \mathrm{H}_{2} \mathrm{O}$
$\mathrm{E}_{\mathrm{Mn}^{2+} / \mathrm{MnO}_{4}^{-}}^{0}=-1.510 \mathrm{~V}$
$\frac{1}{2} \mathrm{O}_{2}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_{2} \mathrm{O}$
$\mathrm{E}_{\mathrm{O}_{2} / \mathrm{H}_{2} \mathrm{O}}^{\mathrm{0}}=1.223 \mathrm{~V}$
Will the permanganate ion, $\mathrm{MnO}_{4}^{-}$liberate $\mathrm{O}_{2}$ from water in the presence of an acid?

1 No, because $\mathrm{E}_{\text {cell }}^{\mathrm{o}}=-2.733 \mathrm{~V}$
2 Yes, because $\mathrm{E}_{\text {cell }}^{\mathrm{o}}=+0.287 \mathrm{~V}$
3 No, because $\mathrm{E}_{\text {cell }}^{\mathrm{o}}=-0.287 \mathrm{~V}$
4 Yes, because $\mathrm{E}_{\text {cell }}^{\mathrm{o}}=+2.733 \mathrm{~V}$
ELECTROCHEMISTRY

276021 When 965 coulombs of electricity is passed through a solution of silver nitrate, the amount of silver deposited is

1 $10.8 \mathrm{~g}$
2 $2.16 \mathrm{~g}$
3 $1.08 \mathrm{~g}$
4 $0.54 \mathrm{~g}$
ELECTROCHEMISTRY

276084 One faraday of current was passed through the electrolytic cells placed in series containing solution of $\mathrm{Ag}^{+}, \mathrm{Ni}^{2+}$ and $\mathrm{Cr}^{3+}$ respectively. The ratio of amounts of $\mathrm{Ag}, \mathrm{Ni}$ and $\mathrm{Cr}$ deposited will be
(At. wt. of $\mathrm{Ag}=108, \mathrm{Ni}=59, \mathrm{Cr}=52$ )

1 $108: 29.5: 17.3$
2 $17.4: 29.5: 108$
3 $1: 2: 3$
4 $108: 59: 52$
ELECTROCHEMISTRY

276020 How many gram of cobalt metal will be deposited, when a solution of cobalt(II) chloride is electrolyzed with a current of 10 amperes for 109 minutes (1 Faraday $=96,500$ $\mathrm{C}$; Atomic mass of $\mathrm{Co}=\mathbf{5 9} \mathrm{u})$

1 4.0
2 20.0
3 40.0
4 0.66
ELECTROCHEMISTRY

275993 Given below are half cell reactions
$\mathrm{MnO}_{4}^{-}+8 \mathrm{H}^{+}+5 \mathrm{e}^{-} \rightarrow \mathrm{Mn}^{2+}+4 \mathrm{H}_{2} \mathrm{O}$
$\mathrm{E}_{\mathrm{Mn}^{2+} / \mathrm{MnO}_{4}^{-}}^{0}=-1.510 \mathrm{~V}$
$\frac{1}{2} \mathrm{O}_{2}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_{2} \mathrm{O}$
$\mathrm{E}_{\mathrm{O}_{2} / \mathrm{H}_{2} \mathrm{O}}^{\mathrm{0}}=1.223 \mathrm{~V}$
Will the permanganate ion, $\mathrm{MnO}_{4}^{-}$liberate $\mathrm{O}_{2}$ from water in the presence of an acid?

1 No, because $\mathrm{E}_{\text {cell }}^{\mathrm{o}}=-2.733 \mathrm{~V}$
2 Yes, because $\mathrm{E}_{\text {cell }}^{\mathrm{o}}=+0.287 \mathrm{~V}$
3 No, because $\mathrm{E}_{\text {cell }}^{\mathrm{o}}=-0.287 \mathrm{~V}$
4 Yes, because $\mathrm{E}_{\text {cell }}^{\mathrm{o}}=+2.733 \mathrm{~V}$
ELECTROCHEMISTRY

276021 When 965 coulombs of electricity is passed through a solution of silver nitrate, the amount of silver deposited is

1 $10.8 \mathrm{~g}$
2 $2.16 \mathrm{~g}$
3 $1.08 \mathrm{~g}$
4 $0.54 \mathrm{~g}$
ELECTROCHEMISTRY

276084 One faraday of current was passed through the electrolytic cells placed in series containing solution of $\mathrm{Ag}^{+}, \mathrm{Ni}^{2+}$ and $\mathrm{Cr}^{3+}$ respectively. The ratio of amounts of $\mathrm{Ag}, \mathrm{Ni}$ and $\mathrm{Cr}$ deposited will be
(At. wt. of $\mathrm{Ag}=108, \mathrm{Ni}=59, \mathrm{Cr}=52$ )

1 $108: 29.5: 17.3$
2 $17.4: 29.5: 108$
3 $1: 2: 3$
4 $108: 59: 52$
ELECTROCHEMISTRY

276020 How many gram of cobalt metal will be deposited, when a solution of cobalt(II) chloride is electrolyzed with a current of 10 amperes for 109 minutes (1 Faraday $=96,500$ $\mathrm{C}$; Atomic mass of $\mathrm{Co}=\mathbf{5 9} \mathrm{u})$

1 4.0
2 20.0
3 40.0
4 0.66
ELECTROCHEMISTRY

275993 Given below are half cell reactions
$\mathrm{MnO}_{4}^{-}+8 \mathrm{H}^{+}+5 \mathrm{e}^{-} \rightarrow \mathrm{Mn}^{2+}+4 \mathrm{H}_{2} \mathrm{O}$
$\mathrm{E}_{\mathrm{Mn}^{2+} / \mathrm{MnO}_{4}^{-}}^{0}=-1.510 \mathrm{~V}$
$\frac{1}{2} \mathrm{O}_{2}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_{2} \mathrm{O}$
$\mathrm{E}_{\mathrm{O}_{2} / \mathrm{H}_{2} \mathrm{O}}^{\mathrm{0}}=1.223 \mathrm{~V}$
Will the permanganate ion, $\mathrm{MnO}_{4}^{-}$liberate $\mathrm{O}_{2}$ from water in the presence of an acid?

1 No, because $\mathrm{E}_{\text {cell }}^{\mathrm{o}}=-2.733 \mathrm{~V}$
2 Yes, because $\mathrm{E}_{\text {cell }}^{\mathrm{o}}=+0.287 \mathrm{~V}$
3 No, because $\mathrm{E}_{\text {cell }}^{\mathrm{o}}=-0.287 \mathrm{~V}$
4 Yes, because $\mathrm{E}_{\text {cell }}^{\mathrm{o}}=+2.733 \mathrm{~V}$
ELECTROCHEMISTRY

276021 When 965 coulombs of electricity is passed through a solution of silver nitrate, the amount of silver deposited is

1 $10.8 \mathrm{~g}$
2 $2.16 \mathrm{~g}$
3 $1.08 \mathrm{~g}$
4 $0.54 \mathrm{~g}$