NEET Test Series from KOTA - 10 Papers In MS WORD
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SOLUTIONS
277579
Gold sol can be prepared by
1 hydrolysis of gold (III) chloride
2 oxidation of gold by aqua-regia
3 peptization
4 treating gold (III) chloride with metallic zinc
5 reduction of gold (III) chloride with formalin solution
Explanation:
Gold solution can be prepared by reduction of gold (III) chloride with formalin solution, So, Reaction will be: $2 \mathrm{AuCl}_{3}+3 \mathrm{HCHO}+3 \mathrm{H}_{2} \mathrm{O} \stackrel{\text { Reduction }}{\longrightarrow} 2 \mathrm{Au}+3 \mathrm{HCOOH}+6 \mathrm{HCl}$
Kerala-CEE-2014
SOLUTIONS
277582
Which one of the following does not involve coagulation?
1 Formation of delta regions
2 Peptization
3 Treatment of drinking water by potash alum
4 Clotting of bloos by the use of ferric chloride
Explanation:
Coagulation is the phenomenon of conversion of colloidal solution into precipitate while in peptization, a fresh precipitate is converted into solution by adding electrolyte. Hence, it is clear that peptization does not involve coagulation.
KARNATAKA-CET
SOLUTIONS
277584
Select wrong statement.
1 If a very small amount of $\mathrm{AlCl}_{3}$ is added to gold solution, coagulation occurs, but if a large quantity of $\mathrm{AlCl}_{3}$ is added, there is no coagulation
2 Organic ions are more strongly absorbed on charged surface in comparison to inorganic ions
3 Both emulsifier and peptising agents stabilize colloidal but their actions are different
4 Colloidal solution are thermodynamically stable.
Explanation:
When an excess of an electrolyte is added, the colloidal particles are precipitated. This is because colloidal particles take ions carrying charge opposite to that present on themselves. This causes neutralization leading to their coagulation.
AMU - 2009
SOLUTIONS
277557
For $\mathrm{As}_{2} \mathrm{~S}_{3}$ sol, the most effective coagulating agent is
1 $\mathrm{CaCO}_{3}$
2 $\mathrm{NaCl}$
3 $\mathrm{FeCl}_{3}$
4 Clay
Explanation:
$\mathrm{AS}_{2} \mathrm{~S}_{3}$ is negative sol. It is obvious that captions are effective in coagulating negative sols. According to hardy Schulze rule greater the valency of the coagulating ion greater is its coagulating power the given $\mathrm{FeCl}_{3}\left(\mathrm{Fe}^{3+}\right)$ is most effective for causing coagulation of $\mathrm{As}_{2} \mathrm{~S}_{3}$ sol.
5 reduction of gold (III) chloride with formalin solution
Explanation:
Gold solution can be prepared by reduction of gold (III) chloride with formalin solution, So, Reaction will be: $2 \mathrm{AuCl}_{3}+3 \mathrm{HCHO}+3 \mathrm{H}_{2} \mathrm{O} \stackrel{\text { Reduction }}{\longrightarrow} 2 \mathrm{Au}+3 \mathrm{HCOOH}+6 \mathrm{HCl}$
Kerala-CEE-2014
SOLUTIONS
277582
Which one of the following does not involve coagulation?
1 Formation of delta regions
2 Peptization
3 Treatment of drinking water by potash alum
4 Clotting of bloos by the use of ferric chloride
Explanation:
Coagulation is the phenomenon of conversion of colloidal solution into precipitate while in peptization, a fresh precipitate is converted into solution by adding electrolyte. Hence, it is clear that peptization does not involve coagulation.
KARNATAKA-CET
SOLUTIONS
277584
Select wrong statement.
1 If a very small amount of $\mathrm{AlCl}_{3}$ is added to gold solution, coagulation occurs, but if a large quantity of $\mathrm{AlCl}_{3}$ is added, there is no coagulation
2 Organic ions are more strongly absorbed on charged surface in comparison to inorganic ions
3 Both emulsifier and peptising agents stabilize colloidal but their actions are different
4 Colloidal solution are thermodynamically stable.
Explanation:
When an excess of an electrolyte is added, the colloidal particles are precipitated. This is because colloidal particles take ions carrying charge opposite to that present on themselves. This causes neutralization leading to their coagulation.
AMU - 2009
SOLUTIONS
277557
For $\mathrm{As}_{2} \mathrm{~S}_{3}$ sol, the most effective coagulating agent is
1 $\mathrm{CaCO}_{3}$
2 $\mathrm{NaCl}$
3 $\mathrm{FeCl}_{3}$
4 Clay
Explanation:
$\mathrm{AS}_{2} \mathrm{~S}_{3}$ is negative sol. It is obvious that captions are effective in coagulating negative sols. According to hardy Schulze rule greater the valency of the coagulating ion greater is its coagulating power the given $\mathrm{FeCl}_{3}\left(\mathrm{Fe}^{3+}\right)$ is most effective for causing coagulation of $\mathrm{As}_{2} \mathrm{~S}_{3}$ sol.
5 reduction of gold (III) chloride with formalin solution
Explanation:
Gold solution can be prepared by reduction of gold (III) chloride with formalin solution, So, Reaction will be: $2 \mathrm{AuCl}_{3}+3 \mathrm{HCHO}+3 \mathrm{H}_{2} \mathrm{O} \stackrel{\text { Reduction }}{\longrightarrow} 2 \mathrm{Au}+3 \mathrm{HCOOH}+6 \mathrm{HCl}$
Kerala-CEE-2014
SOLUTIONS
277582
Which one of the following does not involve coagulation?
1 Formation of delta regions
2 Peptization
3 Treatment of drinking water by potash alum
4 Clotting of bloos by the use of ferric chloride
Explanation:
Coagulation is the phenomenon of conversion of colloidal solution into precipitate while in peptization, a fresh precipitate is converted into solution by adding electrolyte. Hence, it is clear that peptization does not involve coagulation.
KARNATAKA-CET
SOLUTIONS
277584
Select wrong statement.
1 If a very small amount of $\mathrm{AlCl}_{3}$ is added to gold solution, coagulation occurs, but if a large quantity of $\mathrm{AlCl}_{3}$ is added, there is no coagulation
2 Organic ions are more strongly absorbed on charged surface in comparison to inorganic ions
3 Both emulsifier and peptising agents stabilize colloidal but their actions are different
4 Colloidal solution are thermodynamically stable.
Explanation:
When an excess of an electrolyte is added, the colloidal particles are precipitated. This is because colloidal particles take ions carrying charge opposite to that present on themselves. This causes neutralization leading to their coagulation.
AMU - 2009
SOLUTIONS
277557
For $\mathrm{As}_{2} \mathrm{~S}_{3}$ sol, the most effective coagulating agent is
1 $\mathrm{CaCO}_{3}$
2 $\mathrm{NaCl}$
3 $\mathrm{FeCl}_{3}$
4 Clay
Explanation:
$\mathrm{AS}_{2} \mathrm{~S}_{3}$ is negative sol. It is obvious that captions are effective in coagulating negative sols. According to hardy Schulze rule greater the valency of the coagulating ion greater is its coagulating power the given $\mathrm{FeCl}_{3}\left(\mathrm{Fe}^{3+}\right)$ is most effective for causing coagulation of $\mathrm{As}_{2} \mathrm{~S}_{3}$ sol.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
SOLUTIONS
277579
Gold sol can be prepared by
1 hydrolysis of gold (III) chloride
2 oxidation of gold by aqua-regia
3 peptization
4 treating gold (III) chloride with metallic zinc
5 reduction of gold (III) chloride with formalin solution
Explanation:
Gold solution can be prepared by reduction of gold (III) chloride with formalin solution, So, Reaction will be: $2 \mathrm{AuCl}_{3}+3 \mathrm{HCHO}+3 \mathrm{H}_{2} \mathrm{O} \stackrel{\text { Reduction }}{\longrightarrow} 2 \mathrm{Au}+3 \mathrm{HCOOH}+6 \mathrm{HCl}$
Kerala-CEE-2014
SOLUTIONS
277582
Which one of the following does not involve coagulation?
1 Formation of delta regions
2 Peptization
3 Treatment of drinking water by potash alum
4 Clotting of bloos by the use of ferric chloride
Explanation:
Coagulation is the phenomenon of conversion of colloidal solution into precipitate while in peptization, a fresh precipitate is converted into solution by adding electrolyte. Hence, it is clear that peptization does not involve coagulation.
KARNATAKA-CET
SOLUTIONS
277584
Select wrong statement.
1 If a very small amount of $\mathrm{AlCl}_{3}$ is added to gold solution, coagulation occurs, but if a large quantity of $\mathrm{AlCl}_{3}$ is added, there is no coagulation
2 Organic ions are more strongly absorbed on charged surface in comparison to inorganic ions
3 Both emulsifier and peptising agents stabilize colloidal but their actions are different
4 Colloidal solution are thermodynamically stable.
Explanation:
When an excess of an electrolyte is added, the colloidal particles are precipitated. This is because colloidal particles take ions carrying charge opposite to that present on themselves. This causes neutralization leading to their coagulation.
AMU - 2009
SOLUTIONS
277557
For $\mathrm{As}_{2} \mathrm{~S}_{3}$ sol, the most effective coagulating agent is
1 $\mathrm{CaCO}_{3}$
2 $\mathrm{NaCl}$
3 $\mathrm{FeCl}_{3}$
4 Clay
Explanation:
$\mathrm{AS}_{2} \mathrm{~S}_{3}$ is negative sol. It is obvious that captions are effective in coagulating negative sols. According to hardy Schulze rule greater the valency of the coagulating ion greater is its coagulating power the given $\mathrm{FeCl}_{3}\left(\mathrm{Fe}^{3+}\right)$ is most effective for causing coagulation of $\mathrm{As}_{2} \mathrm{~S}_{3}$ sol.