NEET Test Series from KOTA - 10 Papers In MS WORD
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SOLUTIONS
277522
Which of the following pair of solutions is isotonic?
1 A and B
2 A and $\mathrm{C}$
3 B and D
4 B and C
Explanation:
Isotonic solution are those which have the same osmotic pressure $(\pi=\mathrm{iCRT})$. But were we have different concentration of the solution and also they have different vant's huff factors (i). So $10 \mathrm{~g} / \mathrm{L}$ liter of glucose of solution and $10 \mathrm{~g} / \mathrm{L}$ of urea solution is Isotonic solution.
AP-EAMCET-05.07.2022 Shift-II
SOLUTIONS
277525
A $0.5 \mathrm{~g} / \mathrm{L}$ solution of glucose is found to be isotonic with a $2.5 \mathrm{~g} / \mathrm{L}$ solution of an organic compound. What will be that molecular weight of the organic compound?
1 300
2 600
3 900
4 1200
Explanation:
Molarity of glucose solution $\begin{aligned}= & \frac{0.5 \mathrm{~g}}{180 \times 1 \mathrm{~L}} \\ & =0.00277 \mathrm{M}\end{aligned}$ Isotonic solution have equal molar concentrations, hence, molarity of organic compound solution = $0.00277 \mathrm{M}$ $\therefore \text { Molacular weight of compound }=\frac{2.5}{0.00277 \times 1}=900$
UPCPMT-2008
SOLUTIONS
277527
Blood cells will remain as such in
1 hypertonic solution
2 hypotonic solution
3 isotonic solution
4 None of the above
Explanation:
(i) In hypertonic solution, blood cells (living cells) shrink due to plasmolysis (because water comes out of them). (ii) In hypotonic solution, blood cells burst due to endosmosis. (iii) In isotonic solution, blood cells remain as it is because water neither enters in them nor comes out.
UP CPMT-2004
SOLUTIONS
277540
Concentrated hydrochloric acid when kept in open air sometime produces a cloud of white fumes. The explanation for it is that
1 concentrated hydrochloric acid emits atrongly smelling $\mathrm{HCl}$ gas all the time
2 oxygen in air reacts with the emitted $\mathrm{HCl}$ gas to form a cloud of chlorine gas
3 strong affinity of $\mathrm{HCl}$ gas for moisture in air results in forming of droplets of liquid solution which appears like a cloudy smoke
4 due to strong affinity for water, concentrated hydrochloric acid pulls moisture of air towards itself. This moisture forms droplets of water and hence, the cloud.
Explanation:
Oxygen in air reacts with the emitted $\mathrm{HCl}$ gas to form a cloud of chlorine gas. $2 \mathrm{HCl}+\frac{1}{2} \mathrm{O}_{2} \longrightarrow \mathrm{H}_{2} \mathrm{O}+\mathrm{Cl}_{2}$
277522
Which of the following pair of solutions is isotonic?
1 A and B
2 A and $\mathrm{C}$
3 B and D
4 B and C
Explanation:
Isotonic solution are those which have the same osmotic pressure $(\pi=\mathrm{iCRT})$. But were we have different concentration of the solution and also they have different vant's huff factors (i). So $10 \mathrm{~g} / \mathrm{L}$ liter of glucose of solution and $10 \mathrm{~g} / \mathrm{L}$ of urea solution is Isotonic solution.
AP-EAMCET-05.07.2022 Shift-II
SOLUTIONS
277525
A $0.5 \mathrm{~g} / \mathrm{L}$ solution of glucose is found to be isotonic with a $2.5 \mathrm{~g} / \mathrm{L}$ solution of an organic compound. What will be that molecular weight of the organic compound?
1 300
2 600
3 900
4 1200
Explanation:
Molarity of glucose solution $\begin{aligned}= & \frac{0.5 \mathrm{~g}}{180 \times 1 \mathrm{~L}} \\ & =0.00277 \mathrm{M}\end{aligned}$ Isotonic solution have equal molar concentrations, hence, molarity of organic compound solution = $0.00277 \mathrm{M}$ $\therefore \text { Molacular weight of compound }=\frac{2.5}{0.00277 \times 1}=900$
UPCPMT-2008
SOLUTIONS
277527
Blood cells will remain as such in
1 hypertonic solution
2 hypotonic solution
3 isotonic solution
4 None of the above
Explanation:
(i) In hypertonic solution, blood cells (living cells) shrink due to plasmolysis (because water comes out of them). (ii) In hypotonic solution, blood cells burst due to endosmosis. (iii) In isotonic solution, blood cells remain as it is because water neither enters in them nor comes out.
UP CPMT-2004
SOLUTIONS
277540
Concentrated hydrochloric acid when kept in open air sometime produces a cloud of white fumes. The explanation for it is that
1 concentrated hydrochloric acid emits atrongly smelling $\mathrm{HCl}$ gas all the time
2 oxygen in air reacts with the emitted $\mathrm{HCl}$ gas to form a cloud of chlorine gas
3 strong affinity of $\mathrm{HCl}$ gas for moisture in air results in forming of droplets of liquid solution which appears like a cloudy smoke
4 due to strong affinity for water, concentrated hydrochloric acid pulls moisture of air towards itself. This moisture forms droplets of water and hence, the cloud.
Explanation:
Oxygen in air reacts with the emitted $\mathrm{HCl}$ gas to form a cloud of chlorine gas. $2 \mathrm{HCl}+\frac{1}{2} \mathrm{O}_{2} \longrightarrow \mathrm{H}_{2} \mathrm{O}+\mathrm{Cl}_{2}$
277522
Which of the following pair of solutions is isotonic?
1 A and B
2 A and $\mathrm{C}$
3 B and D
4 B and C
Explanation:
Isotonic solution are those which have the same osmotic pressure $(\pi=\mathrm{iCRT})$. But were we have different concentration of the solution and also they have different vant's huff factors (i). So $10 \mathrm{~g} / \mathrm{L}$ liter of glucose of solution and $10 \mathrm{~g} / \mathrm{L}$ of urea solution is Isotonic solution.
AP-EAMCET-05.07.2022 Shift-II
SOLUTIONS
277525
A $0.5 \mathrm{~g} / \mathrm{L}$ solution of glucose is found to be isotonic with a $2.5 \mathrm{~g} / \mathrm{L}$ solution of an organic compound. What will be that molecular weight of the organic compound?
1 300
2 600
3 900
4 1200
Explanation:
Molarity of glucose solution $\begin{aligned}= & \frac{0.5 \mathrm{~g}}{180 \times 1 \mathrm{~L}} \\ & =0.00277 \mathrm{M}\end{aligned}$ Isotonic solution have equal molar concentrations, hence, molarity of organic compound solution = $0.00277 \mathrm{M}$ $\therefore \text { Molacular weight of compound }=\frac{2.5}{0.00277 \times 1}=900$
UPCPMT-2008
SOLUTIONS
277527
Blood cells will remain as such in
1 hypertonic solution
2 hypotonic solution
3 isotonic solution
4 None of the above
Explanation:
(i) In hypertonic solution, blood cells (living cells) shrink due to plasmolysis (because water comes out of them). (ii) In hypotonic solution, blood cells burst due to endosmosis. (iii) In isotonic solution, blood cells remain as it is because water neither enters in them nor comes out.
UP CPMT-2004
SOLUTIONS
277540
Concentrated hydrochloric acid when kept in open air sometime produces a cloud of white fumes. The explanation for it is that
1 concentrated hydrochloric acid emits atrongly smelling $\mathrm{HCl}$ gas all the time
2 oxygen in air reacts with the emitted $\mathrm{HCl}$ gas to form a cloud of chlorine gas
3 strong affinity of $\mathrm{HCl}$ gas for moisture in air results in forming of droplets of liquid solution which appears like a cloudy smoke
4 due to strong affinity for water, concentrated hydrochloric acid pulls moisture of air towards itself. This moisture forms droplets of water and hence, the cloud.
Explanation:
Oxygen in air reacts with the emitted $\mathrm{HCl}$ gas to form a cloud of chlorine gas. $2 \mathrm{HCl}+\frac{1}{2} \mathrm{O}_{2} \longrightarrow \mathrm{H}_{2} \mathrm{O}+\mathrm{Cl}_{2}$
277522
Which of the following pair of solutions is isotonic?
1 A and B
2 A and $\mathrm{C}$
3 B and D
4 B and C
Explanation:
Isotonic solution are those which have the same osmotic pressure $(\pi=\mathrm{iCRT})$. But were we have different concentration of the solution and also they have different vant's huff factors (i). So $10 \mathrm{~g} / \mathrm{L}$ liter of glucose of solution and $10 \mathrm{~g} / \mathrm{L}$ of urea solution is Isotonic solution.
AP-EAMCET-05.07.2022 Shift-II
SOLUTIONS
277525
A $0.5 \mathrm{~g} / \mathrm{L}$ solution of glucose is found to be isotonic with a $2.5 \mathrm{~g} / \mathrm{L}$ solution of an organic compound. What will be that molecular weight of the organic compound?
1 300
2 600
3 900
4 1200
Explanation:
Molarity of glucose solution $\begin{aligned}= & \frac{0.5 \mathrm{~g}}{180 \times 1 \mathrm{~L}} \\ & =0.00277 \mathrm{M}\end{aligned}$ Isotonic solution have equal molar concentrations, hence, molarity of organic compound solution = $0.00277 \mathrm{M}$ $\therefore \text { Molacular weight of compound }=\frac{2.5}{0.00277 \times 1}=900$
UPCPMT-2008
SOLUTIONS
277527
Blood cells will remain as such in
1 hypertonic solution
2 hypotonic solution
3 isotonic solution
4 None of the above
Explanation:
(i) In hypertonic solution, blood cells (living cells) shrink due to plasmolysis (because water comes out of them). (ii) In hypotonic solution, blood cells burst due to endosmosis. (iii) In isotonic solution, blood cells remain as it is because water neither enters in them nor comes out.
UP CPMT-2004
SOLUTIONS
277540
Concentrated hydrochloric acid when kept in open air sometime produces a cloud of white fumes. The explanation for it is that
1 concentrated hydrochloric acid emits atrongly smelling $\mathrm{HCl}$ gas all the time
2 oxygen in air reacts with the emitted $\mathrm{HCl}$ gas to form a cloud of chlorine gas
3 strong affinity of $\mathrm{HCl}$ gas for moisture in air results in forming of droplets of liquid solution which appears like a cloudy smoke
4 due to strong affinity for water, concentrated hydrochloric acid pulls moisture of air towards itself. This moisture forms droplets of water and hence, the cloud.
Explanation:
Oxygen in air reacts with the emitted $\mathrm{HCl}$ gas to form a cloud of chlorine gas. $2 \mathrm{HCl}+\frac{1}{2} \mathrm{O}_{2} \longrightarrow \mathrm{H}_{2} \mathrm{O}+\mathrm{Cl}_{2}$
