230679
In $\stackrel{1}{\mathrm{C}} \mathbf{H}_2=\stackrel{2}{\mathrm{C}}=\stackrel{3}{\mathrm{C}} \mathbf{H}-\stackrel{4}{\mathrm{C}} \mathbf{H}_3$ molecule, the hybridization of carbon $1,2,3$ and 4 respectively,
: The given compound are - Hence, the given mode of hybridisation $\mathrm{sp}^2-\mathrm{sp} \mathrm{p}^2-\mathrm{sp}$ form left to right is $\mathrm{CH}_2=\mathrm{CH}-\mathrm{C} \equiv \mathrm{N}$
230679
In $\stackrel{1}{\mathrm{C}} \mathbf{H}_2=\stackrel{2}{\mathrm{C}}=\stackrel{3}{\mathrm{C}} \mathbf{H}-\stackrel{4}{\mathrm{C}} \mathbf{H}_3$ molecule, the hybridization of carbon $1,2,3$ and 4 respectively,
: The given compound are - Hence, the given mode of hybridisation $\mathrm{sp}^2-\mathrm{sp} \mathrm{p}^2-\mathrm{sp}$ form left to right is $\mathrm{CH}_2=\mathrm{CH}-\mathrm{C} \equiv \mathrm{N}$
230679
In $\stackrel{1}{\mathrm{C}} \mathbf{H}_2=\stackrel{2}{\mathrm{C}}=\stackrel{3}{\mathrm{C}} \mathbf{H}-\stackrel{4}{\mathrm{C}} \mathbf{H}_3$ molecule, the hybridization of carbon $1,2,3$ and 4 respectively,
: The given compound are - Hence, the given mode of hybridisation $\mathrm{sp}^2-\mathrm{sp} \mathrm{p}^2-\mathrm{sp}$ form left to right is $\mathrm{CH}_2=\mathrm{CH}-\mathrm{C} \equiv \mathrm{N}$
230679
In $\stackrel{1}{\mathrm{C}} \mathbf{H}_2=\stackrel{2}{\mathrm{C}}=\stackrel{3}{\mathrm{C}} \mathbf{H}-\stackrel{4}{\mathrm{C}} \mathbf{H}_3$ molecule, the hybridization of carbon $1,2,3$ and 4 respectively,
: The given compound are - Hence, the given mode of hybridisation $\mathrm{sp}^2-\mathrm{sp} \mathrm{p}^2-\mathrm{sp}$ form left to right is $\mathrm{CH}_2=\mathrm{CH}-\mathrm{C} \equiv \mathrm{N}$