: The structure of allyl cyanide is - In allyl cyanide molecule contain 9 sigma bonds, 3?bond and one lone pair respectively.
Kerala-CEE-2013
Hydrocarbons
230660
In dehydrolysing reaction, $\mathrm{CH}_3 \mathrm{CONH}_2 \stackrel{\mathrm{P}_2 \mathrm{O}_3}{\longrightarrow} \mathrm{CH}_3 \mathrm{CN}+\mathrm{H}_2 \mathrm{O}$ the hybridisation state of carbon is changed from
1 $\mathrm{sp}^3$ to $\mathrm{sp}^2$
2 $s p$ to $s p^2$
3 $\mathrm{sp}^2$ to $\mathrm{sp}$
4 $\mathrm{sp}$ to $\mathrm{sp}^3$
Explanation:
: The given dehydrolysing reaction - The hybridisation state of carbon is changed from $\mathrm{sp}^2$ to $\mathrm{sp}$.
CG PET -2008
Hydrocarbons
230661
Hybridization of 1 and 2 carbon atom in $\stackrel{1}{\mathrm{C}} \mathrm{H}_2=$ $\stackrel{2}{\mathrm{C}}=\mathrm{CH}_2$ are
1 $\mathrm{sp}, \mathrm{sp}$
2 $s p^2 \cdot s p^2$
3 $\mathrm{sp}^2, \mathrm{sp}$
4 $\mathrm{sp}^3, \mathrm{sp}^2$
Explanation:
: The hybridisation of 1 and 2 carbon atom are $s p^2$ and $\mathrm{sp}$ respectively.
JIPMER-2005
Hydrocarbons
230662
Hybridization of $\mathrm{C}_2$ and $\mathrm{C}_3$ of $\mathrm{H}_3 \mathrm{C}-\mathrm{CH}=\mathrm{C}=\mathrm{CH}-\mathrm{CH}_3$ are
1 $\mathrm{sp}, \mathrm{sp}^3$
2 $s \mathrm{p}^2, \mathrm{sp}$
3 $\mathrm{sp}^2, \mathrm{sp}^2$
4 $\mathrm{sp}, \mathrm{sp}$
Explanation:
: The hybridissation of $\mathrm{C}_2$ and $\mathrm{C}_3$ of So $\mathrm{C}_2$ and $\mathrm{C}_3$ hybridization is $\mathrm{sp}^2$ and $\mathrm{sp}$.
WB-JEE-2011
Hydrocarbons
230664
The compound in which carbon atom uses $\mathrm{sp}^3$ hybrid orbitals for bond formation?
1 $\mathrm{HCOOH}$
2 $\mathrm{NH}_2 \mathrm{CONH}_2$
3 $\left(\mathrm{CH}_3\right)_3 \mathrm{COH}$
4 $\mathrm{CH}_3 \mathrm{CHO}$
Explanation:
: The hybridisation of the following compound are - In $\left(\mathrm{CH}_3\right)_3 \mathrm{COH}$ has sp3 hybrid orbitals.
: The structure of allyl cyanide is - In allyl cyanide molecule contain 9 sigma bonds, 3?bond and one lone pair respectively.
Kerala-CEE-2013
Hydrocarbons
230660
In dehydrolysing reaction, $\mathrm{CH}_3 \mathrm{CONH}_2 \stackrel{\mathrm{P}_2 \mathrm{O}_3}{\longrightarrow} \mathrm{CH}_3 \mathrm{CN}+\mathrm{H}_2 \mathrm{O}$ the hybridisation state of carbon is changed from
1 $\mathrm{sp}^3$ to $\mathrm{sp}^2$
2 $s p$ to $s p^2$
3 $\mathrm{sp}^2$ to $\mathrm{sp}$
4 $\mathrm{sp}$ to $\mathrm{sp}^3$
Explanation:
: The given dehydrolysing reaction - The hybridisation state of carbon is changed from $\mathrm{sp}^2$ to $\mathrm{sp}$.
CG PET -2008
Hydrocarbons
230661
Hybridization of 1 and 2 carbon atom in $\stackrel{1}{\mathrm{C}} \mathrm{H}_2=$ $\stackrel{2}{\mathrm{C}}=\mathrm{CH}_2$ are
1 $\mathrm{sp}, \mathrm{sp}$
2 $s p^2 \cdot s p^2$
3 $\mathrm{sp}^2, \mathrm{sp}$
4 $\mathrm{sp}^3, \mathrm{sp}^2$
Explanation:
: The hybridisation of 1 and 2 carbon atom are $s p^2$ and $\mathrm{sp}$ respectively.
JIPMER-2005
Hydrocarbons
230662
Hybridization of $\mathrm{C}_2$ and $\mathrm{C}_3$ of $\mathrm{H}_3 \mathrm{C}-\mathrm{CH}=\mathrm{C}=\mathrm{CH}-\mathrm{CH}_3$ are
1 $\mathrm{sp}, \mathrm{sp}^3$
2 $s \mathrm{p}^2, \mathrm{sp}$
3 $\mathrm{sp}^2, \mathrm{sp}^2$
4 $\mathrm{sp}, \mathrm{sp}$
Explanation:
: The hybridissation of $\mathrm{C}_2$ and $\mathrm{C}_3$ of So $\mathrm{C}_2$ and $\mathrm{C}_3$ hybridization is $\mathrm{sp}^2$ and $\mathrm{sp}$.
WB-JEE-2011
Hydrocarbons
230664
The compound in which carbon atom uses $\mathrm{sp}^3$ hybrid orbitals for bond formation?
1 $\mathrm{HCOOH}$
2 $\mathrm{NH}_2 \mathrm{CONH}_2$
3 $\left(\mathrm{CH}_3\right)_3 \mathrm{COH}$
4 $\mathrm{CH}_3 \mathrm{CHO}$
Explanation:
: The hybridisation of the following compound are - In $\left(\mathrm{CH}_3\right)_3 \mathrm{COH}$ has sp3 hybrid orbitals.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Hydrocarbons
230659
Allyl cyanide molecule contains
1 9 sigma bonds, 4 pi bonds and no lone pair
2 9 sigma bonds, 3 pi bonds and one lone pair
3 8 sigma bonds, 5 pi bonds and one lone pair
4 8 sigma bonds, 3 pi bonds and two lone pairs
5 6 sigma bonds, 2 pi bonds and four lone pairs
Explanation:
: The structure of allyl cyanide is - In allyl cyanide molecule contain 9 sigma bonds, 3?bond and one lone pair respectively.
Kerala-CEE-2013
Hydrocarbons
230660
In dehydrolysing reaction, $\mathrm{CH}_3 \mathrm{CONH}_2 \stackrel{\mathrm{P}_2 \mathrm{O}_3}{\longrightarrow} \mathrm{CH}_3 \mathrm{CN}+\mathrm{H}_2 \mathrm{O}$ the hybridisation state of carbon is changed from
1 $\mathrm{sp}^3$ to $\mathrm{sp}^2$
2 $s p$ to $s p^2$
3 $\mathrm{sp}^2$ to $\mathrm{sp}$
4 $\mathrm{sp}$ to $\mathrm{sp}^3$
Explanation:
: The given dehydrolysing reaction - The hybridisation state of carbon is changed from $\mathrm{sp}^2$ to $\mathrm{sp}$.
CG PET -2008
Hydrocarbons
230661
Hybridization of 1 and 2 carbon atom in $\stackrel{1}{\mathrm{C}} \mathrm{H}_2=$ $\stackrel{2}{\mathrm{C}}=\mathrm{CH}_2$ are
1 $\mathrm{sp}, \mathrm{sp}$
2 $s p^2 \cdot s p^2$
3 $\mathrm{sp}^2, \mathrm{sp}$
4 $\mathrm{sp}^3, \mathrm{sp}^2$
Explanation:
: The hybridisation of 1 and 2 carbon atom are $s p^2$ and $\mathrm{sp}$ respectively.
JIPMER-2005
Hydrocarbons
230662
Hybridization of $\mathrm{C}_2$ and $\mathrm{C}_3$ of $\mathrm{H}_3 \mathrm{C}-\mathrm{CH}=\mathrm{C}=\mathrm{CH}-\mathrm{CH}_3$ are
1 $\mathrm{sp}, \mathrm{sp}^3$
2 $s \mathrm{p}^2, \mathrm{sp}$
3 $\mathrm{sp}^2, \mathrm{sp}^2$
4 $\mathrm{sp}, \mathrm{sp}$
Explanation:
: The hybridissation of $\mathrm{C}_2$ and $\mathrm{C}_3$ of So $\mathrm{C}_2$ and $\mathrm{C}_3$ hybridization is $\mathrm{sp}^2$ and $\mathrm{sp}$.
WB-JEE-2011
Hydrocarbons
230664
The compound in which carbon atom uses $\mathrm{sp}^3$ hybrid orbitals for bond formation?
1 $\mathrm{HCOOH}$
2 $\mathrm{NH}_2 \mathrm{CONH}_2$
3 $\left(\mathrm{CH}_3\right)_3 \mathrm{COH}$
4 $\mathrm{CH}_3 \mathrm{CHO}$
Explanation:
: The hybridisation of the following compound are - In $\left(\mathrm{CH}_3\right)_3 \mathrm{COH}$ has sp3 hybrid orbitals.
: The structure of allyl cyanide is - In allyl cyanide molecule contain 9 sigma bonds, 3?bond and one lone pair respectively.
Kerala-CEE-2013
Hydrocarbons
230660
In dehydrolysing reaction, $\mathrm{CH}_3 \mathrm{CONH}_2 \stackrel{\mathrm{P}_2 \mathrm{O}_3}{\longrightarrow} \mathrm{CH}_3 \mathrm{CN}+\mathrm{H}_2 \mathrm{O}$ the hybridisation state of carbon is changed from
1 $\mathrm{sp}^3$ to $\mathrm{sp}^2$
2 $s p$ to $s p^2$
3 $\mathrm{sp}^2$ to $\mathrm{sp}$
4 $\mathrm{sp}$ to $\mathrm{sp}^3$
Explanation:
: The given dehydrolysing reaction - The hybridisation state of carbon is changed from $\mathrm{sp}^2$ to $\mathrm{sp}$.
CG PET -2008
Hydrocarbons
230661
Hybridization of 1 and 2 carbon atom in $\stackrel{1}{\mathrm{C}} \mathrm{H}_2=$ $\stackrel{2}{\mathrm{C}}=\mathrm{CH}_2$ are
1 $\mathrm{sp}, \mathrm{sp}$
2 $s p^2 \cdot s p^2$
3 $\mathrm{sp}^2, \mathrm{sp}$
4 $\mathrm{sp}^3, \mathrm{sp}^2$
Explanation:
: The hybridisation of 1 and 2 carbon atom are $s p^2$ and $\mathrm{sp}$ respectively.
JIPMER-2005
Hydrocarbons
230662
Hybridization of $\mathrm{C}_2$ and $\mathrm{C}_3$ of $\mathrm{H}_3 \mathrm{C}-\mathrm{CH}=\mathrm{C}=\mathrm{CH}-\mathrm{CH}_3$ are
1 $\mathrm{sp}, \mathrm{sp}^3$
2 $s \mathrm{p}^2, \mathrm{sp}$
3 $\mathrm{sp}^2, \mathrm{sp}^2$
4 $\mathrm{sp}, \mathrm{sp}$
Explanation:
: The hybridissation of $\mathrm{C}_2$ and $\mathrm{C}_3$ of So $\mathrm{C}_2$ and $\mathrm{C}_3$ hybridization is $\mathrm{sp}^2$ and $\mathrm{sp}$.
WB-JEE-2011
Hydrocarbons
230664
The compound in which carbon atom uses $\mathrm{sp}^3$ hybrid orbitals for bond formation?
1 $\mathrm{HCOOH}$
2 $\mathrm{NH}_2 \mathrm{CONH}_2$
3 $\left(\mathrm{CH}_3\right)_3 \mathrm{COH}$
4 $\mathrm{CH}_3 \mathrm{CHO}$
Explanation:
: The hybridisation of the following compound are - In $\left(\mathrm{CH}_3\right)_3 \mathrm{COH}$ has sp3 hybrid orbitals.
: The structure of allyl cyanide is - In allyl cyanide molecule contain 9 sigma bonds, 3?bond and one lone pair respectively.
Kerala-CEE-2013
Hydrocarbons
230660
In dehydrolysing reaction, $\mathrm{CH}_3 \mathrm{CONH}_2 \stackrel{\mathrm{P}_2 \mathrm{O}_3}{\longrightarrow} \mathrm{CH}_3 \mathrm{CN}+\mathrm{H}_2 \mathrm{O}$ the hybridisation state of carbon is changed from
1 $\mathrm{sp}^3$ to $\mathrm{sp}^2$
2 $s p$ to $s p^2$
3 $\mathrm{sp}^2$ to $\mathrm{sp}$
4 $\mathrm{sp}$ to $\mathrm{sp}^3$
Explanation:
: The given dehydrolysing reaction - The hybridisation state of carbon is changed from $\mathrm{sp}^2$ to $\mathrm{sp}$.
CG PET -2008
Hydrocarbons
230661
Hybridization of 1 and 2 carbon atom in $\stackrel{1}{\mathrm{C}} \mathrm{H}_2=$ $\stackrel{2}{\mathrm{C}}=\mathrm{CH}_2$ are
1 $\mathrm{sp}, \mathrm{sp}$
2 $s p^2 \cdot s p^2$
3 $\mathrm{sp}^2, \mathrm{sp}$
4 $\mathrm{sp}^3, \mathrm{sp}^2$
Explanation:
: The hybridisation of 1 and 2 carbon atom are $s p^2$ and $\mathrm{sp}$ respectively.
JIPMER-2005
Hydrocarbons
230662
Hybridization of $\mathrm{C}_2$ and $\mathrm{C}_3$ of $\mathrm{H}_3 \mathrm{C}-\mathrm{CH}=\mathrm{C}=\mathrm{CH}-\mathrm{CH}_3$ are
1 $\mathrm{sp}, \mathrm{sp}^3$
2 $s \mathrm{p}^2, \mathrm{sp}$
3 $\mathrm{sp}^2, \mathrm{sp}^2$
4 $\mathrm{sp}, \mathrm{sp}$
Explanation:
: The hybridissation of $\mathrm{C}_2$ and $\mathrm{C}_3$ of So $\mathrm{C}_2$ and $\mathrm{C}_3$ hybridization is $\mathrm{sp}^2$ and $\mathrm{sp}$.
WB-JEE-2011
Hydrocarbons
230664
The compound in which carbon atom uses $\mathrm{sp}^3$ hybrid orbitals for bond formation?
1 $\mathrm{HCOOH}$
2 $\mathrm{NH}_2 \mathrm{CONH}_2$
3 $\left(\mathrm{CH}_3\right)_3 \mathrm{COH}$
4 $\mathrm{CH}_3 \mathrm{CHO}$
Explanation:
: The hybridisation of the following compound are - In $\left(\mathrm{CH}_3\right)_3 \mathrm{COH}$ has sp3 hybrid orbitals.
