230711
The hybridization state of $\mathrm{C}$ atom in butendioic acid is
1 $s \mathrm{p}^2$
2 $\mathrm{sp}^3$
3 Both (a) and (b)
4 $\mathrm{sp}$
Explanation:
: The structure of butendioic acid is - In butendioic acid all the carbon is $\mathrm{sp}^2$ hybridised.
MHT CET-2012
Hydrocarbons
230715
In the hydrocarbon, $\mathrm{C}_6 \mathrm{H}_3-\mathrm{C}_5 \mathrm{C}=\underset{4}{\mathrm{C}} \mathrm{H}-\mathrm{C}_2 \mathrm{H}_2-\underset{2}{\mathrm{C}} \equiv \mathrm{C} \mathrm{H}$ The state of hybridization of carbons 1,3 and 5 are in the following sequence
1 $\mathrm{sp}, \mathrm{sp}^2, \mathrm{sp}^3$
2 $\mathrm{sp}^3, \mathrm{sp}^2, \mathrm{sp}$
3 $\mathrm{sp}^2, \mathrm{sp}, \mathrm{sp}^3$
4 $\mathrm{sp}, \mathrm{sp}^3, \mathrm{sp}^2$
Explanation:
: The given hydrocarbon is - $\mathrm{CH}_3-\underset{5}{\mathrm{CH}}=\underset{4}{\mathrm{CH}}-\underset{3}{\mathrm{CH}_2}-\underset{2}{\mathrm{C}} \equiv \underset{1}{\mathrm{CH}}$ The hybridisation state of carbon 1,3 and 5 are $\mathrm{sp}, \mathrm{sp}^3$ and $\mathrm{sp}^2$.
NEET-2008
Hydrocarbons
230720
The correct sequence of hybridization of methane, ethene and acetylene is
1 $\mathrm{sp}, \mathrm{sp}^2, \mathrm{sp}^3$
2 $\mathrm{sp}^2, \mathrm{sp}^3, \mathrm{sp}$
3 $\mathrm{sp}^3, \mathrm{sp}^2, \mathrm{sp}$
4 $\mathrm{sp}^3, \mathrm{sp}, \mathrm{sp}^2$
Explanation:
: The first bond between any two atoms is sigma and rest are pi bonds. $\mathrm{Pi}_{\mathrm{i}}$ bond is formed by sideways overlapping of unhybridised p-orbital.
UP CPMT-2003
Hydrocarbons
230663
The hybridization of carbon atoms in $\mathrm{C}-\mathrm{C}$ single bond of $\mathrm{HC} \equiv \mathrm{C}-\mathrm{CH}=\mathrm{CH}_2$ is
1 $s p^3-s p^3$
2 $s p^2-s p^2$
3 $\mathrm{sp}-\mathrm{sp}^2$
4 $\mathrm{sp}^3-\mathrm{sp}$
Explanation:
: $\underset{\mathrm{sp}}{\mathrm{CH}} \equiv \underset{\mathrm{sp}}{\mathrm{C}}-\underset{\mathrm{wq}^2}{\mathrm{CH}}=\underset{\mathrm{sp}^2}{\mathrm{CH}_2}$ In the hybridization of carbon atom in $\mathrm{C}-\mathrm{C}$ single bond of $\mathrm{HC} \equiv \mathrm{C}-\mathrm{CH}=\mathrm{CH}_2$ is $\mathrm{sp}-\mathrm{sp}^2$.
J and K CET-(2003)
Hydrocarbons
230666
The hybridization state of carbon atoms in the product formed by the reaction of ethyl chloride with aqueous $\mathrm{KOH}$, is
230711
The hybridization state of $\mathrm{C}$ atom in butendioic acid is
1 $s \mathrm{p}^2$
2 $\mathrm{sp}^3$
3 Both (a) and (b)
4 $\mathrm{sp}$
Explanation:
: The structure of butendioic acid is - In butendioic acid all the carbon is $\mathrm{sp}^2$ hybridised.
MHT CET-2012
Hydrocarbons
230715
In the hydrocarbon, $\mathrm{C}_6 \mathrm{H}_3-\mathrm{C}_5 \mathrm{C}=\underset{4}{\mathrm{C}} \mathrm{H}-\mathrm{C}_2 \mathrm{H}_2-\underset{2}{\mathrm{C}} \equiv \mathrm{C} \mathrm{H}$ The state of hybridization of carbons 1,3 and 5 are in the following sequence
1 $\mathrm{sp}, \mathrm{sp}^2, \mathrm{sp}^3$
2 $\mathrm{sp}^3, \mathrm{sp}^2, \mathrm{sp}$
3 $\mathrm{sp}^2, \mathrm{sp}, \mathrm{sp}^3$
4 $\mathrm{sp}, \mathrm{sp}^3, \mathrm{sp}^2$
Explanation:
: The given hydrocarbon is - $\mathrm{CH}_3-\underset{5}{\mathrm{CH}}=\underset{4}{\mathrm{CH}}-\underset{3}{\mathrm{CH}_2}-\underset{2}{\mathrm{C}} \equiv \underset{1}{\mathrm{CH}}$ The hybridisation state of carbon 1,3 and 5 are $\mathrm{sp}, \mathrm{sp}^3$ and $\mathrm{sp}^2$.
NEET-2008
Hydrocarbons
230720
The correct sequence of hybridization of methane, ethene and acetylene is
1 $\mathrm{sp}, \mathrm{sp}^2, \mathrm{sp}^3$
2 $\mathrm{sp}^2, \mathrm{sp}^3, \mathrm{sp}$
3 $\mathrm{sp}^3, \mathrm{sp}^2, \mathrm{sp}$
4 $\mathrm{sp}^3, \mathrm{sp}, \mathrm{sp}^2$
Explanation:
: The first bond between any two atoms is sigma and rest are pi bonds. $\mathrm{Pi}_{\mathrm{i}}$ bond is formed by sideways overlapping of unhybridised p-orbital.
UP CPMT-2003
Hydrocarbons
230663
The hybridization of carbon atoms in $\mathrm{C}-\mathrm{C}$ single bond of $\mathrm{HC} \equiv \mathrm{C}-\mathrm{CH}=\mathrm{CH}_2$ is
1 $s p^3-s p^3$
2 $s p^2-s p^2$
3 $\mathrm{sp}-\mathrm{sp}^2$
4 $\mathrm{sp}^3-\mathrm{sp}$
Explanation:
: $\underset{\mathrm{sp}}{\mathrm{CH}} \equiv \underset{\mathrm{sp}}{\mathrm{C}}-\underset{\mathrm{wq}^2}{\mathrm{CH}}=\underset{\mathrm{sp}^2}{\mathrm{CH}_2}$ In the hybridization of carbon atom in $\mathrm{C}-\mathrm{C}$ single bond of $\mathrm{HC} \equiv \mathrm{C}-\mathrm{CH}=\mathrm{CH}_2$ is $\mathrm{sp}-\mathrm{sp}^2$.
J and K CET-(2003)
Hydrocarbons
230666
The hybridization state of carbon atoms in the product formed by the reaction of ethyl chloride with aqueous $\mathrm{KOH}$, is
230711
The hybridization state of $\mathrm{C}$ atom in butendioic acid is
1 $s \mathrm{p}^2$
2 $\mathrm{sp}^3$
3 Both (a) and (b)
4 $\mathrm{sp}$
Explanation:
: The structure of butendioic acid is - In butendioic acid all the carbon is $\mathrm{sp}^2$ hybridised.
MHT CET-2012
Hydrocarbons
230715
In the hydrocarbon, $\mathrm{C}_6 \mathrm{H}_3-\mathrm{C}_5 \mathrm{C}=\underset{4}{\mathrm{C}} \mathrm{H}-\mathrm{C}_2 \mathrm{H}_2-\underset{2}{\mathrm{C}} \equiv \mathrm{C} \mathrm{H}$ The state of hybridization of carbons 1,3 and 5 are in the following sequence
1 $\mathrm{sp}, \mathrm{sp}^2, \mathrm{sp}^3$
2 $\mathrm{sp}^3, \mathrm{sp}^2, \mathrm{sp}$
3 $\mathrm{sp}^2, \mathrm{sp}, \mathrm{sp}^3$
4 $\mathrm{sp}, \mathrm{sp}^3, \mathrm{sp}^2$
Explanation:
: The given hydrocarbon is - $\mathrm{CH}_3-\underset{5}{\mathrm{CH}}=\underset{4}{\mathrm{CH}}-\underset{3}{\mathrm{CH}_2}-\underset{2}{\mathrm{C}} \equiv \underset{1}{\mathrm{CH}}$ The hybridisation state of carbon 1,3 and 5 are $\mathrm{sp}, \mathrm{sp}^3$ and $\mathrm{sp}^2$.
NEET-2008
Hydrocarbons
230720
The correct sequence of hybridization of methane, ethene and acetylene is
1 $\mathrm{sp}, \mathrm{sp}^2, \mathrm{sp}^3$
2 $\mathrm{sp}^2, \mathrm{sp}^3, \mathrm{sp}$
3 $\mathrm{sp}^3, \mathrm{sp}^2, \mathrm{sp}$
4 $\mathrm{sp}^3, \mathrm{sp}, \mathrm{sp}^2$
Explanation:
: The first bond between any two atoms is sigma and rest are pi bonds. $\mathrm{Pi}_{\mathrm{i}}$ bond is formed by sideways overlapping of unhybridised p-orbital.
UP CPMT-2003
Hydrocarbons
230663
The hybridization of carbon atoms in $\mathrm{C}-\mathrm{C}$ single bond of $\mathrm{HC} \equiv \mathrm{C}-\mathrm{CH}=\mathrm{CH}_2$ is
1 $s p^3-s p^3$
2 $s p^2-s p^2$
3 $\mathrm{sp}-\mathrm{sp}^2$
4 $\mathrm{sp}^3-\mathrm{sp}$
Explanation:
: $\underset{\mathrm{sp}}{\mathrm{CH}} \equiv \underset{\mathrm{sp}}{\mathrm{C}}-\underset{\mathrm{wq}^2}{\mathrm{CH}}=\underset{\mathrm{sp}^2}{\mathrm{CH}_2}$ In the hybridization of carbon atom in $\mathrm{C}-\mathrm{C}$ single bond of $\mathrm{HC} \equiv \mathrm{C}-\mathrm{CH}=\mathrm{CH}_2$ is $\mathrm{sp}-\mathrm{sp}^2$.
J and K CET-(2003)
Hydrocarbons
230666
The hybridization state of carbon atoms in the product formed by the reaction of ethyl chloride with aqueous $\mathrm{KOH}$, is
230711
The hybridization state of $\mathrm{C}$ atom in butendioic acid is
1 $s \mathrm{p}^2$
2 $\mathrm{sp}^3$
3 Both (a) and (b)
4 $\mathrm{sp}$
Explanation:
: The structure of butendioic acid is - In butendioic acid all the carbon is $\mathrm{sp}^2$ hybridised.
MHT CET-2012
Hydrocarbons
230715
In the hydrocarbon, $\mathrm{C}_6 \mathrm{H}_3-\mathrm{C}_5 \mathrm{C}=\underset{4}{\mathrm{C}} \mathrm{H}-\mathrm{C}_2 \mathrm{H}_2-\underset{2}{\mathrm{C}} \equiv \mathrm{C} \mathrm{H}$ The state of hybridization of carbons 1,3 and 5 are in the following sequence
1 $\mathrm{sp}, \mathrm{sp}^2, \mathrm{sp}^3$
2 $\mathrm{sp}^3, \mathrm{sp}^2, \mathrm{sp}$
3 $\mathrm{sp}^2, \mathrm{sp}, \mathrm{sp}^3$
4 $\mathrm{sp}, \mathrm{sp}^3, \mathrm{sp}^2$
Explanation:
: The given hydrocarbon is - $\mathrm{CH}_3-\underset{5}{\mathrm{CH}}=\underset{4}{\mathrm{CH}}-\underset{3}{\mathrm{CH}_2}-\underset{2}{\mathrm{C}} \equiv \underset{1}{\mathrm{CH}}$ The hybridisation state of carbon 1,3 and 5 are $\mathrm{sp}, \mathrm{sp}^3$ and $\mathrm{sp}^2$.
NEET-2008
Hydrocarbons
230720
The correct sequence of hybridization of methane, ethene and acetylene is
1 $\mathrm{sp}, \mathrm{sp}^2, \mathrm{sp}^3$
2 $\mathrm{sp}^2, \mathrm{sp}^3, \mathrm{sp}$
3 $\mathrm{sp}^3, \mathrm{sp}^2, \mathrm{sp}$
4 $\mathrm{sp}^3, \mathrm{sp}, \mathrm{sp}^2$
Explanation:
: The first bond between any two atoms is sigma and rest are pi bonds. $\mathrm{Pi}_{\mathrm{i}}$ bond is formed by sideways overlapping of unhybridised p-orbital.
UP CPMT-2003
Hydrocarbons
230663
The hybridization of carbon atoms in $\mathrm{C}-\mathrm{C}$ single bond of $\mathrm{HC} \equiv \mathrm{C}-\mathrm{CH}=\mathrm{CH}_2$ is
1 $s p^3-s p^3$
2 $s p^2-s p^2$
3 $\mathrm{sp}-\mathrm{sp}^2$
4 $\mathrm{sp}^3-\mathrm{sp}$
Explanation:
: $\underset{\mathrm{sp}}{\mathrm{CH}} \equiv \underset{\mathrm{sp}}{\mathrm{C}}-\underset{\mathrm{wq}^2}{\mathrm{CH}}=\underset{\mathrm{sp}^2}{\mathrm{CH}_2}$ In the hybridization of carbon atom in $\mathrm{C}-\mathrm{C}$ single bond of $\mathrm{HC} \equiv \mathrm{C}-\mathrm{CH}=\mathrm{CH}_2$ is $\mathrm{sp}-\mathrm{sp}^2$.
J and K CET-(2003)
Hydrocarbons
230666
The hybridization state of carbon atoms in the product formed by the reaction of ethyl chloride with aqueous $\mathrm{KOH}$, is
230711
The hybridization state of $\mathrm{C}$ atom in butendioic acid is
1 $s \mathrm{p}^2$
2 $\mathrm{sp}^3$
3 Both (a) and (b)
4 $\mathrm{sp}$
Explanation:
: The structure of butendioic acid is - In butendioic acid all the carbon is $\mathrm{sp}^2$ hybridised.
MHT CET-2012
Hydrocarbons
230715
In the hydrocarbon, $\mathrm{C}_6 \mathrm{H}_3-\mathrm{C}_5 \mathrm{C}=\underset{4}{\mathrm{C}} \mathrm{H}-\mathrm{C}_2 \mathrm{H}_2-\underset{2}{\mathrm{C}} \equiv \mathrm{C} \mathrm{H}$ The state of hybridization of carbons 1,3 and 5 are in the following sequence
1 $\mathrm{sp}, \mathrm{sp}^2, \mathrm{sp}^3$
2 $\mathrm{sp}^3, \mathrm{sp}^2, \mathrm{sp}$
3 $\mathrm{sp}^2, \mathrm{sp}, \mathrm{sp}^3$
4 $\mathrm{sp}, \mathrm{sp}^3, \mathrm{sp}^2$
Explanation:
: The given hydrocarbon is - $\mathrm{CH}_3-\underset{5}{\mathrm{CH}}=\underset{4}{\mathrm{CH}}-\underset{3}{\mathrm{CH}_2}-\underset{2}{\mathrm{C}} \equiv \underset{1}{\mathrm{CH}}$ The hybridisation state of carbon 1,3 and 5 are $\mathrm{sp}, \mathrm{sp}^3$ and $\mathrm{sp}^2$.
NEET-2008
Hydrocarbons
230720
The correct sequence of hybridization of methane, ethene and acetylene is
1 $\mathrm{sp}, \mathrm{sp}^2, \mathrm{sp}^3$
2 $\mathrm{sp}^2, \mathrm{sp}^3, \mathrm{sp}$
3 $\mathrm{sp}^3, \mathrm{sp}^2, \mathrm{sp}$
4 $\mathrm{sp}^3, \mathrm{sp}, \mathrm{sp}^2$
Explanation:
: The first bond between any two atoms is sigma and rest are pi bonds. $\mathrm{Pi}_{\mathrm{i}}$ bond is formed by sideways overlapping of unhybridised p-orbital.
UP CPMT-2003
Hydrocarbons
230663
The hybridization of carbon atoms in $\mathrm{C}-\mathrm{C}$ single bond of $\mathrm{HC} \equiv \mathrm{C}-\mathrm{CH}=\mathrm{CH}_2$ is
1 $s p^3-s p^3$
2 $s p^2-s p^2$
3 $\mathrm{sp}-\mathrm{sp}^2$
4 $\mathrm{sp}^3-\mathrm{sp}$
Explanation:
: $\underset{\mathrm{sp}}{\mathrm{CH}} \equiv \underset{\mathrm{sp}}{\mathrm{C}}-\underset{\mathrm{wq}^2}{\mathrm{CH}}=\underset{\mathrm{sp}^2}{\mathrm{CH}_2}$ In the hybridization of carbon atom in $\mathrm{C}-\mathrm{C}$ single bond of $\mathrm{HC} \equiv \mathrm{C}-\mathrm{CH}=\mathrm{CH}_2$ is $\mathrm{sp}-\mathrm{sp}^2$.
J and K CET-(2003)
Hydrocarbons
230666
The hybridization state of carbon atoms in the product formed by the reaction of ethyl chloride with aqueous $\mathrm{KOH}$, is
