NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Hydrocarbons
230502
Electrophile in the case of chlorination of benzene in the presence of $\mathrm{FeCl}_3$ is
1 $\mathrm{Cl}$
2 $\mathrm{FeCl}_3$
3 $\mathrm{Cl}^{+}$
4 $\mathrm{Cl}^{-}$
Explanation:
:
NEET-1996
Hydrocarbons
230504
In which of the following molecules, all atoms are coplanar?
1
2
3
4
Explanation:
: Coplanar means atoms a groups of atom that lie on the same plane. Biphenyl has both Benzene rings on the same plane. When all atoms of a compound are in the same plane are called coplanar compound coplanarity in organic compounds is seen in unsaturated molecues.
NEET-II 2016
Hydrocarbons
230505
When acetylene is passed through dil, $\mathrm{H}_2 \mathrm{SO}_4$ in the presence of $\mathrm{HgSO}_4$, the compound formed is
1 acetic acid
2 ketone
3 ether
4 acetaldehyde
Explanation:
: Acetylene add a ater molecule when treated with dil $\mathrm{H}_2 \mathrm{SO}_4$ in the presence of $\mathrm{HgSO}_4$ to form acetal dehyde (ethanal).
NEET-1999
Hydrocarbons
230507
The restricted rotation about carbon carbon double bond in 2-butene is due to
1 overlap of one $\mathrm{s}$ and $\mathrm{sp}^2$-hybridized orbitals
2 overlap of two $\mathrm{sp}^2$-hybridized orbitals
3 overlap of one $\mathrm{p}$ and one $s \mathrm{p}^2$-hybridized orbitals
4 sideways overlap of two p-orbitals
Explanation:
: Restricted rotation about carbon-Carbon double bond in 2-butene is due to sideways overlAP of 2 p-orbital's $\pi$-bond gives rigidity to molecule, the rotation around the double bond is prevented. The restriction in free rotation makes the position of groups attached to $\mathrm{sp}^2$ hybrid.
230502
Electrophile in the case of chlorination of benzene in the presence of $\mathrm{FeCl}_3$ is
1 $\mathrm{Cl}$
2 $\mathrm{FeCl}_3$
3 $\mathrm{Cl}^{+}$
4 $\mathrm{Cl}^{-}$
Explanation:
:
NEET-1996
Hydrocarbons
230504
In which of the following molecules, all atoms are coplanar?
1
2
3
4
Explanation:
: Coplanar means atoms a groups of atom that lie on the same plane. Biphenyl has both Benzene rings on the same plane. When all atoms of a compound are in the same plane are called coplanar compound coplanarity in organic compounds is seen in unsaturated molecues.
NEET-II 2016
Hydrocarbons
230505
When acetylene is passed through dil, $\mathrm{H}_2 \mathrm{SO}_4$ in the presence of $\mathrm{HgSO}_4$, the compound formed is
1 acetic acid
2 ketone
3 ether
4 acetaldehyde
Explanation:
: Acetylene add a ater molecule when treated with dil $\mathrm{H}_2 \mathrm{SO}_4$ in the presence of $\mathrm{HgSO}_4$ to form acetal dehyde (ethanal).
NEET-1999
Hydrocarbons
230507
The restricted rotation about carbon carbon double bond in 2-butene is due to
1 overlap of one $\mathrm{s}$ and $\mathrm{sp}^2$-hybridized orbitals
2 overlap of two $\mathrm{sp}^2$-hybridized orbitals
3 overlap of one $\mathrm{p}$ and one $s \mathrm{p}^2$-hybridized orbitals
4 sideways overlap of two p-orbitals
Explanation:
: Restricted rotation about carbon-Carbon double bond in 2-butene is due to sideways overlAP of 2 p-orbital's $\pi$-bond gives rigidity to molecule, the rotation around the double bond is prevented. The restriction in free rotation makes the position of groups attached to $\mathrm{sp}^2$ hybrid.
230502
Electrophile in the case of chlorination of benzene in the presence of $\mathrm{FeCl}_3$ is
1 $\mathrm{Cl}$
2 $\mathrm{FeCl}_3$
3 $\mathrm{Cl}^{+}$
4 $\mathrm{Cl}^{-}$
Explanation:
:
NEET-1996
Hydrocarbons
230504
In which of the following molecules, all atoms are coplanar?
1
2
3
4
Explanation:
: Coplanar means atoms a groups of atom that lie on the same plane. Biphenyl has both Benzene rings on the same plane. When all atoms of a compound are in the same plane are called coplanar compound coplanarity in organic compounds is seen in unsaturated molecues.
NEET-II 2016
Hydrocarbons
230505
When acetylene is passed through dil, $\mathrm{H}_2 \mathrm{SO}_4$ in the presence of $\mathrm{HgSO}_4$, the compound formed is
1 acetic acid
2 ketone
3 ether
4 acetaldehyde
Explanation:
: Acetylene add a ater molecule when treated with dil $\mathrm{H}_2 \mathrm{SO}_4$ in the presence of $\mathrm{HgSO}_4$ to form acetal dehyde (ethanal).
NEET-1999
Hydrocarbons
230507
The restricted rotation about carbon carbon double bond in 2-butene is due to
1 overlap of one $\mathrm{s}$ and $\mathrm{sp}^2$-hybridized orbitals
2 overlap of two $\mathrm{sp}^2$-hybridized orbitals
3 overlap of one $\mathrm{p}$ and one $s \mathrm{p}^2$-hybridized orbitals
4 sideways overlap of two p-orbitals
Explanation:
: Restricted rotation about carbon-Carbon double bond in 2-butene is due to sideways overlAP of 2 p-orbital's $\pi$-bond gives rigidity to molecule, the rotation around the double bond is prevented. The restriction in free rotation makes the position of groups attached to $\mathrm{sp}^2$ hybrid.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Hydrocarbons
230502
Electrophile in the case of chlorination of benzene in the presence of $\mathrm{FeCl}_3$ is
1 $\mathrm{Cl}$
2 $\mathrm{FeCl}_3$
3 $\mathrm{Cl}^{+}$
4 $\mathrm{Cl}^{-}$
Explanation:
:
NEET-1996
Hydrocarbons
230504
In which of the following molecules, all atoms are coplanar?
1
2
3
4
Explanation:
: Coplanar means atoms a groups of atom that lie on the same plane. Biphenyl has both Benzene rings on the same plane. When all atoms of a compound are in the same plane are called coplanar compound coplanarity in organic compounds is seen in unsaturated molecues.
NEET-II 2016
Hydrocarbons
230505
When acetylene is passed through dil, $\mathrm{H}_2 \mathrm{SO}_4$ in the presence of $\mathrm{HgSO}_4$, the compound formed is
1 acetic acid
2 ketone
3 ether
4 acetaldehyde
Explanation:
: Acetylene add a ater molecule when treated with dil $\mathrm{H}_2 \mathrm{SO}_4$ in the presence of $\mathrm{HgSO}_4$ to form acetal dehyde (ethanal).
NEET-1999
Hydrocarbons
230507
The restricted rotation about carbon carbon double bond in 2-butene is due to
1 overlap of one $\mathrm{s}$ and $\mathrm{sp}^2$-hybridized orbitals
2 overlap of two $\mathrm{sp}^2$-hybridized orbitals
3 overlap of one $\mathrm{p}$ and one $s \mathrm{p}^2$-hybridized orbitals
4 sideways overlap of two p-orbitals
Explanation:
: Restricted rotation about carbon-Carbon double bond in 2-butene is due to sideways overlAP of 2 p-orbital's $\pi$-bond gives rigidity to molecule, the rotation around the double bond is prevented. The restriction in free rotation makes the position of groups attached to $\mathrm{sp}^2$ hybrid.
