230269
The compounds formed at anode in the electrolysis of an aqueous solution of potassium acetate, are
1 $\mathrm{C}_2 \mathrm{H}_6$ and $\mathrm{CO}_2$
2 $\mathrm{C}_2 \mathrm{H}_4$ and $\mathrm{CO}_2$
3 $\mathrm{CH}_4$ and $\mathrm{H}_2$
4 $\mathrm{CH}_4$ and $\mathrm{CO}_2$
Explanation:
: This is an example of Kolbe's electrolysis. $2 \mathrm{CH}_3 \mathrm{COOK} \stackrel{\text { electrolysis }}{\longrightarrow} 2 \mathrm{CH}_3 \mathrm{COO}^{-}+2 \mathrm{~K}^{+}$ At cathode: From above reaction it is clear that ethane formed anode.
UP CPMT-2008
Hydrocarbons
230257
Consider the nitration of benzene using mixed conc, $\mathrm{H}_2 \mathrm{SO}_4$ and $\mathrm{HNO}_3$. If a large amount of $\mathrm{KHSO}_4$ is added to the mixture, the rate of nitration will be
1 Unchanged
2 Doubled
3 Faster
4 Slower
Explanation:
: $\mathrm{HNO}_3+\mathrm{H}_2 \mathrm{SO}_4 \square \mathrm{NO}_2^{+}+\mathrm{HSO}_4^{-}+\mathrm{H}_2 \mathrm{O}$ In the nitration of benzene in the presence of conc, $\mathrm{H}_2 \mathrm{SO}_4$ and $\mathrm{HNO}_3$ benzene is formed. It large amount of $\mathrm{KHSO}_4$ is added to this mixture more $\mathrm{HSO}_4^{-}$in furnisnes and hence the concentration of electrophile decreases, rate of electrophilic aromatic reaction slow down.
NEET-I 2016
Hydrocarbons
230261
Reactivity of hydrogen atoms attached to different carbon atoms in alkanes has the order
1 teritary $>$ primary $>$ secondary
2 primary $>$ secondary $>$ tertiary
3 both (a) and (b)
4 teritiary $>$ secondary $>$ primary
Explanation:
: The reactivity of $\mathrm{H}$-atoms depend upon the stability of free radical follows the order-Tertiary $>$ Secondary $>$ Primary. Therefore, reactivity of $\mathrm{H}$ - atom follows the same order i.e., tertiary $>$ secondary $>$ primary. Tertiary alkanes are more reactive because they form tertiary free radical which is more stable.
NEET-1993
Hydrocarbons
230262
Which of the following reaction is expected to readily give a hydrocarbon product in good yields?
: Electrolysis of sodium or potassium salt of carboxylic acid gives good yield of hydrocarbon. \(2 \mathrm{RCOOK} \xrightarrow[\text { Oxidation }]{\text { Electrolysis }} \mathrm{R}-\mathrm{R}+2 \mathrm{CO}_2\)
NEET-1997
Hydrocarbons
230265
Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon containing less than four carbon atoms (A) is
1 $\mathrm{CH} \equiv \mathrm{CH}$
2 $\mathrm{CH}_2 \equiv \mathrm{CH}_2$
3 $\mathrm{CH}_3-\mathrm{CH}_3$
4 $\mathrm{CH}_4$
Explanation:
: Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide $\mathrm{CH}_4+\mathrm{Br}_2 \rightarrow \mathrm{CH}_3-\mathrm{Br}+\mathrm{HBr}$ Mothane $\quad$ Allyillosomide. Methyl bromide by wurtz reaction is converted into a gaseous hydrocarbon containing less than four carbon. $2 \mathrm{CH}_3 \mathrm{Br}+2 \mathrm{Na} \rightarrow \mathrm{CH}_3-\mathrm{CH}_3+2 \mathrm{NaBr}$
230269
The compounds formed at anode in the electrolysis of an aqueous solution of potassium acetate, are
1 $\mathrm{C}_2 \mathrm{H}_6$ and $\mathrm{CO}_2$
2 $\mathrm{C}_2 \mathrm{H}_4$ and $\mathrm{CO}_2$
3 $\mathrm{CH}_4$ and $\mathrm{H}_2$
4 $\mathrm{CH}_4$ and $\mathrm{CO}_2$
Explanation:
: This is an example of Kolbe's electrolysis. $2 \mathrm{CH}_3 \mathrm{COOK} \stackrel{\text { electrolysis }}{\longrightarrow} 2 \mathrm{CH}_3 \mathrm{COO}^{-}+2 \mathrm{~K}^{+}$ At cathode: From above reaction it is clear that ethane formed anode.
UP CPMT-2008
Hydrocarbons
230257
Consider the nitration of benzene using mixed conc, $\mathrm{H}_2 \mathrm{SO}_4$ and $\mathrm{HNO}_3$. If a large amount of $\mathrm{KHSO}_4$ is added to the mixture, the rate of nitration will be
1 Unchanged
2 Doubled
3 Faster
4 Slower
Explanation:
: $\mathrm{HNO}_3+\mathrm{H}_2 \mathrm{SO}_4 \square \mathrm{NO}_2^{+}+\mathrm{HSO}_4^{-}+\mathrm{H}_2 \mathrm{O}$ In the nitration of benzene in the presence of conc, $\mathrm{H}_2 \mathrm{SO}_4$ and $\mathrm{HNO}_3$ benzene is formed. It large amount of $\mathrm{KHSO}_4$ is added to this mixture more $\mathrm{HSO}_4^{-}$in furnisnes and hence the concentration of electrophile decreases, rate of electrophilic aromatic reaction slow down.
NEET-I 2016
Hydrocarbons
230261
Reactivity of hydrogen atoms attached to different carbon atoms in alkanes has the order
1 teritary $>$ primary $>$ secondary
2 primary $>$ secondary $>$ tertiary
3 both (a) and (b)
4 teritiary $>$ secondary $>$ primary
Explanation:
: The reactivity of $\mathrm{H}$-atoms depend upon the stability of free radical follows the order-Tertiary $>$ Secondary $>$ Primary. Therefore, reactivity of $\mathrm{H}$ - atom follows the same order i.e., tertiary $>$ secondary $>$ primary. Tertiary alkanes are more reactive because they form tertiary free radical which is more stable.
NEET-1993
Hydrocarbons
230262
Which of the following reaction is expected to readily give a hydrocarbon product in good yields?
: Electrolysis of sodium or potassium salt of carboxylic acid gives good yield of hydrocarbon. \(2 \mathrm{RCOOK} \xrightarrow[\text { Oxidation }]{\text { Electrolysis }} \mathrm{R}-\mathrm{R}+2 \mathrm{CO}_2\)
NEET-1997
Hydrocarbons
230265
Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon containing less than four carbon atoms (A) is
1 $\mathrm{CH} \equiv \mathrm{CH}$
2 $\mathrm{CH}_2 \equiv \mathrm{CH}_2$
3 $\mathrm{CH}_3-\mathrm{CH}_3$
4 $\mathrm{CH}_4$
Explanation:
: Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide $\mathrm{CH}_4+\mathrm{Br}_2 \rightarrow \mathrm{CH}_3-\mathrm{Br}+\mathrm{HBr}$ Mothane $\quad$ Allyillosomide. Methyl bromide by wurtz reaction is converted into a gaseous hydrocarbon containing less than four carbon. $2 \mathrm{CH}_3 \mathrm{Br}+2 \mathrm{Na} \rightarrow \mathrm{CH}_3-\mathrm{CH}_3+2 \mathrm{NaBr}$
230269
The compounds formed at anode in the electrolysis of an aqueous solution of potassium acetate, are
1 $\mathrm{C}_2 \mathrm{H}_6$ and $\mathrm{CO}_2$
2 $\mathrm{C}_2 \mathrm{H}_4$ and $\mathrm{CO}_2$
3 $\mathrm{CH}_4$ and $\mathrm{H}_2$
4 $\mathrm{CH}_4$ and $\mathrm{CO}_2$
Explanation:
: This is an example of Kolbe's electrolysis. $2 \mathrm{CH}_3 \mathrm{COOK} \stackrel{\text { electrolysis }}{\longrightarrow} 2 \mathrm{CH}_3 \mathrm{COO}^{-}+2 \mathrm{~K}^{+}$ At cathode: From above reaction it is clear that ethane formed anode.
UP CPMT-2008
Hydrocarbons
230257
Consider the nitration of benzene using mixed conc, $\mathrm{H}_2 \mathrm{SO}_4$ and $\mathrm{HNO}_3$. If a large amount of $\mathrm{KHSO}_4$ is added to the mixture, the rate of nitration will be
1 Unchanged
2 Doubled
3 Faster
4 Slower
Explanation:
: $\mathrm{HNO}_3+\mathrm{H}_2 \mathrm{SO}_4 \square \mathrm{NO}_2^{+}+\mathrm{HSO}_4^{-}+\mathrm{H}_2 \mathrm{O}$ In the nitration of benzene in the presence of conc, $\mathrm{H}_2 \mathrm{SO}_4$ and $\mathrm{HNO}_3$ benzene is formed. It large amount of $\mathrm{KHSO}_4$ is added to this mixture more $\mathrm{HSO}_4^{-}$in furnisnes and hence the concentration of electrophile decreases, rate of electrophilic aromatic reaction slow down.
NEET-I 2016
Hydrocarbons
230261
Reactivity of hydrogen atoms attached to different carbon atoms in alkanes has the order
1 teritary $>$ primary $>$ secondary
2 primary $>$ secondary $>$ tertiary
3 both (a) and (b)
4 teritiary $>$ secondary $>$ primary
Explanation:
: The reactivity of $\mathrm{H}$-atoms depend upon the stability of free radical follows the order-Tertiary $>$ Secondary $>$ Primary. Therefore, reactivity of $\mathrm{H}$ - atom follows the same order i.e., tertiary $>$ secondary $>$ primary. Tertiary alkanes are more reactive because they form tertiary free radical which is more stable.
NEET-1993
Hydrocarbons
230262
Which of the following reaction is expected to readily give a hydrocarbon product in good yields?
: Electrolysis of sodium or potassium salt of carboxylic acid gives good yield of hydrocarbon. \(2 \mathrm{RCOOK} \xrightarrow[\text { Oxidation }]{\text { Electrolysis }} \mathrm{R}-\mathrm{R}+2 \mathrm{CO}_2\)
NEET-1997
Hydrocarbons
230265
Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon containing less than four carbon atoms (A) is
1 $\mathrm{CH} \equiv \mathrm{CH}$
2 $\mathrm{CH}_2 \equiv \mathrm{CH}_2$
3 $\mathrm{CH}_3-\mathrm{CH}_3$
4 $\mathrm{CH}_4$
Explanation:
: Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide $\mathrm{CH}_4+\mathrm{Br}_2 \rightarrow \mathrm{CH}_3-\mathrm{Br}+\mathrm{HBr}$ Mothane $\quad$ Allyillosomide. Methyl bromide by wurtz reaction is converted into a gaseous hydrocarbon containing less than four carbon. $2 \mathrm{CH}_3 \mathrm{Br}+2 \mathrm{Na} \rightarrow \mathrm{CH}_3-\mathrm{CH}_3+2 \mathrm{NaBr}$
230269
The compounds formed at anode in the electrolysis of an aqueous solution of potassium acetate, are
1 $\mathrm{C}_2 \mathrm{H}_6$ and $\mathrm{CO}_2$
2 $\mathrm{C}_2 \mathrm{H}_4$ and $\mathrm{CO}_2$
3 $\mathrm{CH}_4$ and $\mathrm{H}_2$
4 $\mathrm{CH}_4$ and $\mathrm{CO}_2$
Explanation:
: This is an example of Kolbe's electrolysis. $2 \mathrm{CH}_3 \mathrm{COOK} \stackrel{\text { electrolysis }}{\longrightarrow} 2 \mathrm{CH}_3 \mathrm{COO}^{-}+2 \mathrm{~K}^{+}$ At cathode: From above reaction it is clear that ethane formed anode.
UP CPMT-2008
Hydrocarbons
230257
Consider the nitration of benzene using mixed conc, $\mathrm{H}_2 \mathrm{SO}_4$ and $\mathrm{HNO}_3$. If a large amount of $\mathrm{KHSO}_4$ is added to the mixture, the rate of nitration will be
1 Unchanged
2 Doubled
3 Faster
4 Slower
Explanation:
: $\mathrm{HNO}_3+\mathrm{H}_2 \mathrm{SO}_4 \square \mathrm{NO}_2^{+}+\mathrm{HSO}_4^{-}+\mathrm{H}_2 \mathrm{O}$ In the nitration of benzene in the presence of conc, $\mathrm{H}_2 \mathrm{SO}_4$ and $\mathrm{HNO}_3$ benzene is formed. It large amount of $\mathrm{KHSO}_4$ is added to this mixture more $\mathrm{HSO}_4^{-}$in furnisnes and hence the concentration of electrophile decreases, rate of electrophilic aromatic reaction slow down.
NEET-I 2016
Hydrocarbons
230261
Reactivity of hydrogen atoms attached to different carbon atoms in alkanes has the order
1 teritary $>$ primary $>$ secondary
2 primary $>$ secondary $>$ tertiary
3 both (a) and (b)
4 teritiary $>$ secondary $>$ primary
Explanation:
: The reactivity of $\mathrm{H}$-atoms depend upon the stability of free radical follows the order-Tertiary $>$ Secondary $>$ Primary. Therefore, reactivity of $\mathrm{H}$ - atom follows the same order i.e., tertiary $>$ secondary $>$ primary. Tertiary alkanes are more reactive because they form tertiary free radical which is more stable.
NEET-1993
Hydrocarbons
230262
Which of the following reaction is expected to readily give a hydrocarbon product in good yields?
: Electrolysis of sodium or potassium salt of carboxylic acid gives good yield of hydrocarbon. \(2 \mathrm{RCOOK} \xrightarrow[\text { Oxidation }]{\text { Electrolysis }} \mathrm{R}-\mathrm{R}+2 \mathrm{CO}_2\)
NEET-1997
Hydrocarbons
230265
Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon containing less than four carbon atoms (A) is
1 $\mathrm{CH} \equiv \mathrm{CH}$
2 $\mathrm{CH}_2 \equiv \mathrm{CH}_2$
3 $\mathrm{CH}_3-\mathrm{CH}_3$
4 $\mathrm{CH}_4$
Explanation:
: Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide $\mathrm{CH}_4+\mathrm{Br}_2 \rightarrow \mathrm{CH}_3-\mathrm{Br}+\mathrm{HBr}$ Mothane $\quad$ Allyillosomide. Methyl bromide by wurtz reaction is converted into a gaseous hydrocarbon containing less than four carbon. $2 \mathrm{CH}_3 \mathrm{Br}+2 \mathrm{Na} \rightarrow \mathrm{CH}_3-\mathrm{CH}_3+2 \mathrm{NaBr}$
230269
The compounds formed at anode in the electrolysis of an aqueous solution of potassium acetate, are
1 $\mathrm{C}_2 \mathrm{H}_6$ and $\mathrm{CO}_2$
2 $\mathrm{C}_2 \mathrm{H}_4$ and $\mathrm{CO}_2$
3 $\mathrm{CH}_4$ and $\mathrm{H}_2$
4 $\mathrm{CH}_4$ and $\mathrm{CO}_2$
Explanation:
: This is an example of Kolbe's electrolysis. $2 \mathrm{CH}_3 \mathrm{COOK} \stackrel{\text { electrolysis }}{\longrightarrow} 2 \mathrm{CH}_3 \mathrm{COO}^{-}+2 \mathrm{~K}^{+}$ At cathode: From above reaction it is clear that ethane formed anode.
UP CPMT-2008
Hydrocarbons
230257
Consider the nitration of benzene using mixed conc, $\mathrm{H}_2 \mathrm{SO}_4$ and $\mathrm{HNO}_3$. If a large amount of $\mathrm{KHSO}_4$ is added to the mixture, the rate of nitration will be
1 Unchanged
2 Doubled
3 Faster
4 Slower
Explanation:
: $\mathrm{HNO}_3+\mathrm{H}_2 \mathrm{SO}_4 \square \mathrm{NO}_2^{+}+\mathrm{HSO}_4^{-}+\mathrm{H}_2 \mathrm{O}$ In the nitration of benzene in the presence of conc, $\mathrm{H}_2 \mathrm{SO}_4$ and $\mathrm{HNO}_3$ benzene is formed. It large amount of $\mathrm{KHSO}_4$ is added to this mixture more $\mathrm{HSO}_4^{-}$in furnisnes and hence the concentration of electrophile decreases, rate of electrophilic aromatic reaction slow down.
NEET-I 2016
Hydrocarbons
230261
Reactivity of hydrogen atoms attached to different carbon atoms in alkanes has the order
1 teritary $>$ primary $>$ secondary
2 primary $>$ secondary $>$ tertiary
3 both (a) and (b)
4 teritiary $>$ secondary $>$ primary
Explanation:
: The reactivity of $\mathrm{H}$-atoms depend upon the stability of free radical follows the order-Tertiary $>$ Secondary $>$ Primary. Therefore, reactivity of $\mathrm{H}$ - atom follows the same order i.e., tertiary $>$ secondary $>$ primary. Tertiary alkanes are more reactive because they form tertiary free radical which is more stable.
NEET-1993
Hydrocarbons
230262
Which of the following reaction is expected to readily give a hydrocarbon product in good yields?
: Electrolysis of sodium or potassium salt of carboxylic acid gives good yield of hydrocarbon. \(2 \mathrm{RCOOK} \xrightarrow[\text { Oxidation }]{\text { Electrolysis }} \mathrm{R}-\mathrm{R}+2 \mathrm{CO}_2\)
NEET-1997
Hydrocarbons
230265
Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon containing less than four carbon atoms (A) is
1 $\mathrm{CH} \equiv \mathrm{CH}$
2 $\mathrm{CH}_2 \equiv \mathrm{CH}_2$
3 $\mathrm{CH}_3-\mathrm{CH}_3$
4 $\mathrm{CH}_4$
Explanation:
: Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide $\mathrm{CH}_4+\mathrm{Br}_2 \rightarrow \mathrm{CH}_3-\mathrm{Br}+\mathrm{HBr}$ Mothane $\quad$ Allyillosomide. Methyl bromide by wurtz reaction is converted into a gaseous hydrocarbon containing less than four carbon. $2 \mathrm{CH}_3 \mathrm{Br}+2 \mathrm{Na} \rightarrow \mathrm{CH}_3-\mathrm{CH}_3+2 \mathrm{NaBr}$
