230142
The reaction of choloroform with alcoholic $\mathrm{KOH}$ and p-toluidine forms
1
2
3
4
Explanation:
: The carbylamine reaction is a chemical test for detection of primary amines in this relations the $\mathrm{p}$ toluidine is heated with allotropic potassium hydroxide and chloroform. It a primary amine is preset, the isocynaide carbylamines is formed with are fact-smelling substances.
Assam CEE-2018
Hydrocarbons
230144
The correct increasing order of boiling points is
: Boiling point increase when number of carbon atom (carbon chain) increas. Boiling point decreases when the branching increase. Hence, the increasing boiling point is - Ethanol $<$ butan-2-o1 < butan-1-ol $<$ pentan-1-ol
Assam CEE-2021
Hydrocarbons
230150
Among the following select the alkane that is expected to have lowest boiling point.
1 hexane
2 2-methyl pentane
3 3-methyl pentane
4 2,2-dimethylbutane
Explanation:
: Boiling point $\propto$ molecular weight $\propto \frac{1}{\text { Branching }}$ The structures of the given alkane are - Hence, the lowest boiling point is 2, 2-dimethyl butane.
BCECE-2018
Hydrocarbons
230152
Which of the following compound can not be used in preparation of iodoform?
1 $\mathrm{CH}_3 \mathrm{CHO}$
2 $\mathrm{CH}_3 \mathrm{COCH}_3$
3 $\mathrm{HCHO}$
4 2-propanol
Explanation:
: The compound containing the group give the positive iodoform test but those compound not containing the group give iodoform test. In formaldehyde can not used in the preparation of idoform test.
230142
The reaction of choloroform with alcoholic $\mathrm{KOH}$ and p-toluidine forms
1
2
3
4
Explanation:
: The carbylamine reaction is a chemical test for detection of primary amines in this relations the $\mathrm{p}$ toluidine is heated with allotropic potassium hydroxide and chloroform. It a primary amine is preset, the isocynaide carbylamines is formed with are fact-smelling substances.
Assam CEE-2018
Hydrocarbons
230144
The correct increasing order of boiling points is
: Boiling point increase when number of carbon atom (carbon chain) increas. Boiling point decreases when the branching increase. Hence, the increasing boiling point is - Ethanol $<$ butan-2-o1 < butan-1-ol $<$ pentan-1-ol
Assam CEE-2021
Hydrocarbons
230150
Among the following select the alkane that is expected to have lowest boiling point.
1 hexane
2 2-methyl pentane
3 3-methyl pentane
4 2,2-dimethylbutane
Explanation:
: Boiling point $\propto$ molecular weight $\propto \frac{1}{\text { Branching }}$ The structures of the given alkane are - Hence, the lowest boiling point is 2, 2-dimethyl butane.
BCECE-2018
Hydrocarbons
230152
Which of the following compound can not be used in preparation of iodoform?
1 $\mathrm{CH}_3 \mathrm{CHO}$
2 $\mathrm{CH}_3 \mathrm{COCH}_3$
3 $\mathrm{HCHO}$
4 2-propanol
Explanation:
: The compound containing the group give the positive iodoform test but those compound not containing the group give iodoform test. In formaldehyde can not used in the preparation of idoform test.
NEET Test Series from KOTA - 10 Papers In MS WORD
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Hydrocarbons
230142
The reaction of choloroform with alcoholic $\mathrm{KOH}$ and p-toluidine forms
1
2
3
4
Explanation:
: The carbylamine reaction is a chemical test for detection of primary amines in this relations the $\mathrm{p}$ toluidine is heated with allotropic potassium hydroxide and chloroform. It a primary amine is preset, the isocynaide carbylamines is formed with are fact-smelling substances.
Assam CEE-2018
Hydrocarbons
230144
The correct increasing order of boiling points is
: Boiling point increase when number of carbon atom (carbon chain) increas. Boiling point decreases when the branching increase. Hence, the increasing boiling point is - Ethanol $<$ butan-2-o1 < butan-1-ol $<$ pentan-1-ol
Assam CEE-2021
Hydrocarbons
230150
Among the following select the alkane that is expected to have lowest boiling point.
1 hexane
2 2-methyl pentane
3 3-methyl pentane
4 2,2-dimethylbutane
Explanation:
: Boiling point $\propto$ molecular weight $\propto \frac{1}{\text { Branching }}$ The structures of the given alkane are - Hence, the lowest boiling point is 2, 2-dimethyl butane.
BCECE-2018
Hydrocarbons
230152
Which of the following compound can not be used in preparation of iodoform?
1 $\mathrm{CH}_3 \mathrm{CHO}$
2 $\mathrm{CH}_3 \mathrm{COCH}_3$
3 $\mathrm{HCHO}$
4 2-propanol
Explanation:
: The compound containing the group give the positive iodoform test but those compound not containing the group give iodoform test. In formaldehyde can not used in the preparation of idoform test.
230142
The reaction of choloroform with alcoholic $\mathrm{KOH}$ and p-toluidine forms
1
2
3
4
Explanation:
: The carbylamine reaction is a chemical test for detection of primary amines in this relations the $\mathrm{p}$ toluidine is heated with allotropic potassium hydroxide and chloroform. It a primary amine is preset, the isocynaide carbylamines is formed with are fact-smelling substances.
Assam CEE-2018
Hydrocarbons
230144
The correct increasing order of boiling points is
: Boiling point increase when number of carbon atom (carbon chain) increas. Boiling point decreases when the branching increase. Hence, the increasing boiling point is - Ethanol $<$ butan-2-o1 < butan-1-ol $<$ pentan-1-ol
Assam CEE-2021
Hydrocarbons
230150
Among the following select the alkane that is expected to have lowest boiling point.
1 hexane
2 2-methyl pentane
3 3-methyl pentane
4 2,2-dimethylbutane
Explanation:
: Boiling point $\propto$ molecular weight $\propto \frac{1}{\text { Branching }}$ The structures of the given alkane are - Hence, the lowest boiling point is 2, 2-dimethyl butane.
BCECE-2018
Hydrocarbons
230152
Which of the following compound can not be used in preparation of iodoform?
1 $\mathrm{CH}_3 \mathrm{CHO}$
2 $\mathrm{CH}_3 \mathrm{COCH}_3$
3 $\mathrm{HCHO}$
4 2-propanol
Explanation:
: The compound containing the group give the positive iodoform test but those compound not containing the group give iodoform test. In formaldehyde can not used in the preparation of idoform test.
give the positive iodoform test but those
give iodoform test.