229829 $20 \mathrm{~mL}$ of $0.1 \mathrm{M}$ acetic acid is mixed in a solution of $\mathrm{NaOH}$. If $10 \mathrm{~mL}$ of $0.1 \mathrm{M} \mathrm{NaOH}$ is present then $\mathrm{H}^{+}$concentration in resulting solution is $\left(\mathrm{K}_{\mathrm{a}}\right.$ of acetic acid $=1.7 \times 10^{-5}$ )
229829 $20 \mathrm{~mL}$ of $0.1 \mathrm{M}$ acetic acid is mixed in a solution of $\mathrm{NaOH}$. If $10 \mathrm{~mL}$ of $0.1 \mathrm{M} \mathrm{NaOH}$ is present then $\mathrm{H}^{+}$concentration in resulting solution is $\left(\mathrm{K}_{\mathrm{a}}\right.$ of acetic acid $=1.7 \times 10^{-5}$ )
229829 $20 \mathrm{~mL}$ of $0.1 \mathrm{M}$ acetic acid is mixed in a solution of $\mathrm{NaOH}$. If $10 \mathrm{~mL}$ of $0.1 \mathrm{M} \mathrm{NaOH}$ is present then $\mathrm{H}^{+}$concentration in resulting solution is $\left(\mathrm{K}_{\mathrm{a}}\right.$ of acetic acid $=1.7 \times 10^{-5}$ )
229829 $20 \mathrm{~mL}$ of $0.1 \mathrm{M}$ acetic acid is mixed in a solution of $\mathrm{NaOH}$. If $10 \mathrm{~mL}$ of $0.1 \mathrm{M} \mathrm{NaOH}$ is present then $\mathrm{H}^{+}$concentration in resulting solution is $\left(\mathrm{K}_{\mathrm{a}}\right.$ of acetic acid $=1.7 \times 10^{-5}$ )
229829 $20 \mathrm{~mL}$ of $0.1 \mathrm{M}$ acetic acid is mixed in a solution of $\mathrm{NaOH}$. If $10 \mathrm{~mL}$ of $0.1 \mathrm{M} \mathrm{NaOH}$ is present then $\mathrm{H}^{+}$concentration in resulting solution is $\left(\mathrm{K}_{\mathrm{a}}\right.$ of acetic acid $=1.7 \times 10^{-5}$ )