229452 A solution contains $0.05 \mathrm{M} \mathrm{NaCl}$ and $0.05 \mathrm{M}$ NaI. The concentration of iodied ion in solution when $\mathrm{AgCl}$ just starts precipitating is equal to $\left(\mathrm{K}_{\mathrm{sp}} \mathrm{AgCl}=1 \times 10^{-10} ; \mathrm{K}_{\mathrm{sp}} \mathrm{AgI}=4 \times 10^{-16}\right.$ )
229452 A solution contains $0.05 \mathrm{M} \mathrm{NaCl}$ and $0.05 \mathrm{M}$ NaI. The concentration of iodied ion in solution when $\mathrm{AgCl}$ just starts precipitating is equal to $\left(\mathrm{K}_{\mathrm{sp}} \mathrm{AgCl}=1 \times 10^{-10} ; \mathrm{K}_{\mathrm{sp}} \mathrm{AgI}=4 \times 10^{-16}\right.$ )
229452 A solution contains $0.05 \mathrm{M} \mathrm{NaCl}$ and $0.05 \mathrm{M}$ NaI. The concentration of iodied ion in solution when $\mathrm{AgCl}$ just starts precipitating is equal to $\left(\mathrm{K}_{\mathrm{sp}} \mathrm{AgCl}=1 \times 10^{-10} ; \mathrm{K}_{\mathrm{sp}} \mathrm{AgI}=4 \times 10^{-16}\right.$ )
229452 A solution contains $0.05 \mathrm{M} \mathrm{NaCl}$ and $0.05 \mathrm{M}$ NaI. The concentration of iodied ion in solution when $\mathrm{AgCl}$ just starts precipitating is equal to $\left(\mathrm{K}_{\mathrm{sp}} \mathrm{AgCl}=1 \times 10^{-10} ; \mathrm{K}_{\mathrm{sp}} \mathrm{AgI}=4 \times 10^{-16}\right.$ )
229452 A solution contains $0.05 \mathrm{M} \mathrm{NaCl}$ and $0.05 \mathrm{M}$ NaI. The concentration of iodied ion in solution when $\mathrm{AgCl}$ just starts precipitating is equal to $\left(\mathrm{K}_{\mathrm{sp}} \mathrm{AgCl}=1 \times 10^{-10} ; \mathrm{K}_{\mathrm{sp}} \mathrm{AgI}=4 \times 10^{-16}\right.$ )