NEET Test Series from KOTA - 10 Papers In MS WORD
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Classification of Elements and Periodicity in Properties
89701
Born-Haber cycle can be used to estimate
1 electronegativity
2 electron affintiy
3 ionic radii
4 All of these
Explanation:
The Born Haber- Cycle can be used to estimate the electron gain enthalpy, electron affinity, lattice energy of ionic solid, dissociation energy, heat of formation etc. Born Haber cycle cannot be estimate by the electronegativity and hydration energy, ionic radii etc.
2008
Classification of Elements and Periodicity in Properties
89714
Which of the following atoms should have the highest $I^{\text {st }}$ electron affinity?
1 $F$
2 $\mathrm{O}$
3 $\mathrm{N}$
4 $\mathrm{C}$
Explanation:
Fluorine has highest first electron affinity because on moving left to right in a period the electron affinity increases.
WB-JEE-2017
Classification of Elements and Periodicity in Properties
89696
Which halogen has the maximum electron affinity?
1 Fluorine
2 Chlorine
3 Bromine
4 Iodine
Explanation:
On moving down a group, generally, electron affinity decreases. But in fluorine, due to its smaller size, the incoming electron experiences greater force of repulsion and hence, its electron affinity is lesser as compared to the electron affinity of chlorine. Thus, among the given, electron affinity is maximum for chlorine.
BCECE-2007
Classification of Elements and Periodicity in Properties
89697
The correct order of electron affinity of $\mathrm{F}$, Cl, $\mathrm{Br}$ and $\mathrm{I}$ is
1 F $>\mathrm{Cl}>\mathrm{Br}>$ I
2 $\mathrm{Cl}>\mathrm{F}>\mathrm{Br}>\mathrm{I}$
3 I $>\mathrm{Br}>\mathrm{Cl}>\mathrm{F}$
4 Br $>$ I $>\mathrm{Cl}>\mathrm{F}$
Explanation:
Electron affinity of elements decreases on going from top to bottom in a group. But, electron affinity of fluorine is unexpectedly lower than that of chlorine. This can be explained as follows:- Fluorine atom is small. So, electron charge density of Fatom is very high. The added electron will experience strong electron-electron repulsion. As a result, when an electron is added to $\mathrm{F}$ atom a certain amount of energy is absorbed, and the net energy released during the formation of anion is lesser. However, if an electron is added to a relatively large p-orbital $3 \mathrm{p}$ in the case of $\mathrm{Cl}$ ), electron-electron repulsion is minimised, and higher electron affinity is observed.
Classification of Elements and Periodicity in Properties
89701
Born-Haber cycle can be used to estimate
1 electronegativity
2 electron affintiy
3 ionic radii
4 All of these
Explanation:
The Born Haber- Cycle can be used to estimate the electron gain enthalpy, electron affinity, lattice energy of ionic solid, dissociation energy, heat of formation etc. Born Haber cycle cannot be estimate by the electronegativity and hydration energy, ionic radii etc.
2008
Classification of Elements and Periodicity in Properties
89714
Which of the following atoms should have the highest $I^{\text {st }}$ electron affinity?
1 $F$
2 $\mathrm{O}$
3 $\mathrm{N}$
4 $\mathrm{C}$
Explanation:
Fluorine has highest first electron affinity because on moving left to right in a period the electron affinity increases.
WB-JEE-2017
Classification of Elements and Periodicity in Properties
89696
Which halogen has the maximum electron affinity?
1 Fluorine
2 Chlorine
3 Bromine
4 Iodine
Explanation:
On moving down a group, generally, electron affinity decreases. But in fluorine, due to its smaller size, the incoming electron experiences greater force of repulsion and hence, its electron affinity is lesser as compared to the electron affinity of chlorine. Thus, among the given, electron affinity is maximum for chlorine.
BCECE-2007
Classification of Elements and Periodicity in Properties
89697
The correct order of electron affinity of $\mathrm{F}$, Cl, $\mathrm{Br}$ and $\mathrm{I}$ is
1 F $>\mathrm{Cl}>\mathrm{Br}>$ I
2 $\mathrm{Cl}>\mathrm{F}>\mathrm{Br}>\mathrm{I}$
3 I $>\mathrm{Br}>\mathrm{Cl}>\mathrm{F}$
4 Br $>$ I $>\mathrm{Cl}>\mathrm{F}$
Explanation:
Electron affinity of elements decreases on going from top to bottom in a group. But, electron affinity of fluorine is unexpectedly lower than that of chlorine. This can be explained as follows:- Fluorine atom is small. So, electron charge density of Fatom is very high. The added electron will experience strong electron-electron repulsion. As a result, when an electron is added to $\mathrm{F}$ atom a certain amount of energy is absorbed, and the net energy released during the formation of anion is lesser. However, if an electron is added to a relatively large p-orbital $3 \mathrm{p}$ in the case of $\mathrm{Cl}$ ), electron-electron repulsion is minimised, and higher electron affinity is observed.
Classification of Elements and Periodicity in Properties
89701
Born-Haber cycle can be used to estimate
1 electronegativity
2 electron affintiy
3 ionic radii
4 All of these
Explanation:
The Born Haber- Cycle can be used to estimate the electron gain enthalpy, electron affinity, lattice energy of ionic solid, dissociation energy, heat of formation etc. Born Haber cycle cannot be estimate by the electronegativity and hydration energy, ionic radii etc.
2008
Classification of Elements and Periodicity in Properties
89714
Which of the following atoms should have the highest $I^{\text {st }}$ electron affinity?
1 $F$
2 $\mathrm{O}$
3 $\mathrm{N}$
4 $\mathrm{C}$
Explanation:
Fluorine has highest first electron affinity because on moving left to right in a period the electron affinity increases.
WB-JEE-2017
Classification of Elements and Periodicity in Properties
89696
Which halogen has the maximum electron affinity?
1 Fluorine
2 Chlorine
3 Bromine
4 Iodine
Explanation:
On moving down a group, generally, electron affinity decreases. But in fluorine, due to its smaller size, the incoming electron experiences greater force of repulsion and hence, its electron affinity is lesser as compared to the electron affinity of chlorine. Thus, among the given, electron affinity is maximum for chlorine.
BCECE-2007
Classification of Elements and Periodicity in Properties
89697
The correct order of electron affinity of $\mathrm{F}$, Cl, $\mathrm{Br}$ and $\mathrm{I}$ is
1 F $>\mathrm{Cl}>\mathrm{Br}>$ I
2 $\mathrm{Cl}>\mathrm{F}>\mathrm{Br}>\mathrm{I}$
3 I $>\mathrm{Br}>\mathrm{Cl}>\mathrm{F}$
4 Br $>$ I $>\mathrm{Cl}>\mathrm{F}$
Explanation:
Electron affinity of elements decreases on going from top to bottom in a group. But, electron affinity of fluorine is unexpectedly lower than that of chlorine. This can be explained as follows:- Fluorine atom is small. So, electron charge density of Fatom is very high. The added electron will experience strong electron-electron repulsion. As a result, when an electron is added to $\mathrm{F}$ atom a certain amount of energy is absorbed, and the net energy released during the formation of anion is lesser. However, if an electron is added to a relatively large p-orbital $3 \mathrm{p}$ in the case of $\mathrm{Cl}$ ), electron-electron repulsion is minimised, and higher electron affinity is observed.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Classification of Elements and Periodicity in Properties
89701
Born-Haber cycle can be used to estimate
1 electronegativity
2 electron affintiy
3 ionic radii
4 All of these
Explanation:
The Born Haber- Cycle can be used to estimate the electron gain enthalpy, electron affinity, lattice energy of ionic solid, dissociation energy, heat of formation etc. Born Haber cycle cannot be estimate by the electronegativity and hydration energy, ionic radii etc.
2008
Classification of Elements and Periodicity in Properties
89714
Which of the following atoms should have the highest $I^{\text {st }}$ electron affinity?
1 $F$
2 $\mathrm{O}$
3 $\mathrm{N}$
4 $\mathrm{C}$
Explanation:
Fluorine has highest first electron affinity because on moving left to right in a period the electron affinity increases.
WB-JEE-2017
Classification of Elements and Periodicity in Properties
89696
Which halogen has the maximum electron affinity?
1 Fluorine
2 Chlorine
3 Bromine
4 Iodine
Explanation:
On moving down a group, generally, electron affinity decreases. But in fluorine, due to its smaller size, the incoming electron experiences greater force of repulsion and hence, its electron affinity is lesser as compared to the electron affinity of chlorine. Thus, among the given, electron affinity is maximum for chlorine.
BCECE-2007
Classification of Elements and Periodicity in Properties
89697
The correct order of electron affinity of $\mathrm{F}$, Cl, $\mathrm{Br}$ and $\mathrm{I}$ is
1 F $>\mathrm{Cl}>\mathrm{Br}>$ I
2 $\mathrm{Cl}>\mathrm{F}>\mathrm{Br}>\mathrm{I}$
3 I $>\mathrm{Br}>\mathrm{Cl}>\mathrm{F}$
4 Br $>$ I $>\mathrm{Cl}>\mathrm{F}$
Explanation:
Electron affinity of elements decreases on going from top to bottom in a group. But, electron affinity of fluorine is unexpectedly lower than that of chlorine. This can be explained as follows:- Fluorine atom is small. So, electron charge density of Fatom is very high. The added electron will experience strong electron-electron repulsion. As a result, when an electron is added to $\mathrm{F}$ atom a certain amount of energy is absorbed, and the net energy released during the formation of anion is lesser. However, if an electron is added to a relatively large p-orbital $3 \mathrm{p}$ in the case of $\mathrm{Cl}$ ), electron-electron repulsion is minimised, and higher electron affinity is observed.