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Classification of Elements and Periodicity in Properties

89514 Which has the smallest size?
4. Electro Negativity

{Na}^{+}

{Mg}^{2 +}

{Al}^{3 +}

P^{5 +}

Explanation:

The smallest size is $P^{5 +}$ because having maximum nuclear charge per electron. When nuclear charge increases then atomic size decreases.

JEE Main

Classification of Elements and Periodicity in Properties

89429 Assertion (A) : Beryllium and aluminum forms $Be F_{4}^{2 -}$ and $Al F_{6}^{3 -}$ Reason(R) : Both $B^{2 +}$ and ${Al}^{3 +}$ have almost same ionic radius The correct option among the following is

1 (A) is true, (R) is true and (R) is the correct explanation for (A)

2 (A) is true, (R) is true but (R) is not the correct explanation for (A)

3 (A) is true but (R) is false

4 (A) is false but (R) is true

Explanation:

Beryllium and aluminum forms ${BeF}_{4}^{- 2}$ and ${AlF}_{6}^{3 -}$ and ${Be}^{+ 2}$ and ${Al}^{+ 3}$ have almost same ionic radius due to about same electronegativity, polarizing power and charge/radius radio, of their ion.