Classification of Elements and Periodicity in Properties
89413
The ionic radii (in $\AA$ ) of $\mathrm{N}^{3-}, \mathrm{O}^{2-}$, and $\mathrm{F}^{-}$ respectively are
1 $1.36,1.40$ and 1.71
2 $1.36,1.71$ and 1.40
3 $1.71,1.40$, and 1.36
4 $1.71,1.36$ and 1.40
Explanation:
Z/e increase then the atomic radii decreases. Hence, the ionic radii of $\mathrm{N}^{3-}, \mathrm{O}^{2-}$ and $\mathrm{F}^{-}$are $1.71,1.40$ and $1.36 \AA$ respectively.
CG PET - 2018
Classification of Elements and Periodicity in Properties
89415
Due to lanthanoid contraction elements exhibit similar radii.
1 $\mathrm{Zn}$ and $\mathrm{Hg}$
2 $\mathrm{Zr}$ and $\mathrm{Hf}$
3 Zr and Y
4 $\mathrm{Ag}$ and $\mathrm{Cd}$
Explanation:
Due to lanthanoid contraction, $\mathrm{Zr}$ and $\mathrm{Hf}$ elements exhibit similar radii. This contraction came into effect due to the poor shielding of $4 f$ electrons because of the poor shielding effect, the attraction on the electrons by the nucleus increases and hence, radius decreases.
NEET-2021
Classification of Elements and Periodicity in Properties
89421
The correct order of ionic radius of nitrogen family is
On moving down top to bottom in a group atomic radii increase due to new shell are added. Thus, the order of ionic radius of nitrogen family are $\mathrm{N}^{3-}<\mathrm{P}^{3-}<\mathrm{As}^{3-}<\mathrm{Sb}^{3-}<\mathrm{Bi}^{3-}$
CG PET- 2015
Classification of Elements and Periodicity in Properties
Effective nuclear charge (i.e. Z/e ratio) decreases from $\mathrm{F}^{-}$to $\mathrm{N}^{3-}$. Hence, the radii follows the order : $\mathrm{F}^{-}<\mathrm{O}^{2-}<\mathrm{N}^{3-}$. Z/e for $\mathrm{F}^{-}=9 / 10=0.9$, for $\mathrm{O}^{2-}=$ $8 / 10=0.8$, for $\mathrm{N}^{3-}=0.7$
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Classification of Elements and Periodicity in Properties
89413
The ionic radii (in $\AA$ ) of $\mathrm{N}^{3-}, \mathrm{O}^{2-}$, and $\mathrm{F}^{-}$ respectively are
1 $1.36,1.40$ and 1.71
2 $1.36,1.71$ and 1.40
3 $1.71,1.40$, and 1.36
4 $1.71,1.36$ and 1.40
Explanation:
Z/e increase then the atomic radii decreases. Hence, the ionic radii of $\mathrm{N}^{3-}, \mathrm{O}^{2-}$ and $\mathrm{F}^{-}$are $1.71,1.40$ and $1.36 \AA$ respectively.
CG PET - 2018
Classification of Elements and Periodicity in Properties
89415
Due to lanthanoid contraction elements exhibit similar radii.
1 $\mathrm{Zn}$ and $\mathrm{Hg}$
2 $\mathrm{Zr}$ and $\mathrm{Hf}$
3 Zr and Y
4 $\mathrm{Ag}$ and $\mathrm{Cd}$
Explanation:
Due to lanthanoid contraction, $\mathrm{Zr}$ and $\mathrm{Hf}$ elements exhibit similar radii. This contraction came into effect due to the poor shielding of $4 f$ electrons because of the poor shielding effect, the attraction on the electrons by the nucleus increases and hence, radius decreases.
NEET-2021
Classification of Elements and Periodicity in Properties
89421
The correct order of ionic radius of nitrogen family is
On moving down top to bottom in a group atomic radii increase due to new shell are added. Thus, the order of ionic radius of nitrogen family are $\mathrm{N}^{3-}<\mathrm{P}^{3-}<\mathrm{As}^{3-}<\mathrm{Sb}^{3-}<\mathrm{Bi}^{3-}$
CG PET- 2015
Classification of Elements and Periodicity in Properties
Effective nuclear charge (i.e. Z/e ratio) decreases from $\mathrm{F}^{-}$to $\mathrm{N}^{3-}$. Hence, the radii follows the order : $\mathrm{F}^{-}<\mathrm{O}^{2-}<\mathrm{N}^{3-}$. Z/e for $\mathrm{F}^{-}=9 / 10=0.9$, for $\mathrm{O}^{2-}=$ $8 / 10=0.8$, for $\mathrm{N}^{3-}=0.7$
Classification of Elements and Periodicity in Properties
89413
The ionic radii (in $\AA$ ) of $\mathrm{N}^{3-}, \mathrm{O}^{2-}$, and $\mathrm{F}^{-}$ respectively are
1 $1.36,1.40$ and 1.71
2 $1.36,1.71$ and 1.40
3 $1.71,1.40$, and 1.36
4 $1.71,1.36$ and 1.40
Explanation:
Z/e increase then the atomic radii decreases. Hence, the ionic radii of $\mathrm{N}^{3-}, \mathrm{O}^{2-}$ and $\mathrm{F}^{-}$are $1.71,1.40$ and $1.36 \AA$ respectively.
CG PET - 2018
Classification of Elements and Periodicity in Properties
89415
Due to lanthanoid contraction elements exhibit similar radii.
1 $\mathrm{Zn}$ and $\mathrm{Hg}$
2 $\mathrm{Zr}$ and $\mathrm{Hf}$
3 Zr and Y
4 $\mathrm{Ag}$ and $\mathrm{Cd}$
Explanation:
Due to lanthanoid contraction, $\mathrm{Zr}$ and $\mathrm{Hf}$ elements exhibit similar radii. This contraction came into effect due to the poor shielding of $4 f$ electrons because of the poor shielding effect, the attraction on the electrons by the nucleus increases and hence, radius decreases.
NEET-2021
Classification of Elements and Periodicity in Properties
89421
The correct order of ionic radius of nitrogen family is
On moving down top to bottom in a group atomic radii increase due to new shell are added. Thus, the order of ionic radius of nitrogen family are $\mathrm{N}^{3-}<\mathrm{P}^{3-}<\mathrm{As}^{3-}<\mathrm{Sb}^{3-}<\mathrm{Bi}^{3-}$
CG PET- 2015
Classification of Elements and Periodicity in Properties
Effective nuclear charge (i.e. Z/e ratio) decreases from $\mathrm{F}^{-}$to $\mathrm{N}^{3-}$. Hence, the radii follows the order : $\mathrm{F}^{-}<\mathrm{O}^{2-}<\mathrm{N}^{3-}$. Z/e for $\mathrm{F}^{-}=9 / 10=0.9$, for $\mathrm{O}^{2-}=$ $8 / 10=0.8$, for $\mathrm{N}^{3-}=0.7$
Classification of Elements and Periodicity in Properties
89413
The ionic radii (in $\AA$ ) of $\mathrm{N}^{3-}, \mathrm{O}^{2-}$, and $\mathrm{F}^{-}$ respectively are
1 $1.36,1.40$ and 1.71
2 $1.36,1.71$ and 1.40
3 $1.71,1.40$, and 1.36
4 $1.71,1.36$ and 1.40
Explanation:
Z/e increase then the atomic radii decreases. Hence, the ionic radii of $\mathrm{N}^{3-}, \mathrm{O}^{2-}$ and $\mathrm{F}^{-}$are $1.71,1.40$ and $1.36 \AA$ respectively.
CG PET - 2018
Classification of Elements and Periodicity in Properties
89415
Due to lanthanoid contraction elements exhibit similar radii.
1 $\mathrm{Zn}$ and $\mathrm{Hg}$
2 $\mathrm{Zr}$ and $\mathrm{Hf}$
3 Zr and Y
4 $\mathrm{Ag}$ and $\mathrm{Cd}$
Explanation:
Due to lanthanoid contraction, $\mathrm{Zr}$ and $\mathrm{Hf}$ elements exhibit similar radii. This contraction came into effect due to the poor shielding of $4 f$ electrons because of the poor shielding effect, the attraction on the electrons by the nucleus increases and hence, radius decreases.
NEET-2021
Classification of Elements and Periodicity in Properties
89421
The correct order of ionic radius of nitrogen family is
On moving down top to bottom in a group atomic radii increase due to new shell are added. Thus, the order of ionic radius of nitrogen family are $\mathrm{N}^{3-}<\mathrm{P}^{3-}<\mathrm{As}^{3-}<\mathrm{Sb}^{3-}<\mathrm{Bi}^{3-}$
CG PET- 2015
Classification of Elements and Periodicity in Properties
Effective nuclear charge (i.e. Z/e ratio) decreases from $\mathrm{F}^{-}$to $\mathrm{N}^{3-}$. Hence, the radii follows the order : $\mathrm{F}^{-}<\mathrm{O}^{2-}<\mathrm{N}^{3-}$. Z/e for $\mathrm{F}^{-}=9 / 10=0.9$, for $\mathrm{O}^{2-}=$ $8 / 10=0.8$, for $\mathrm{N}^{3-}=0.7$
