QBManager

Structure of Atom

239065 The electrons identified by quantum numbers
(i) $n = 4, 1 = 1$
(ii) $n = 4, 1 = 0$
(iii) $n = 3, 1 = 2$
(iv) $n = 2, 1 = 1$
Can be placed in order of increasing energy from the lowest to highest as

1 (iv)

<

(ii)

<

(iii)

<

(i)

2 (ii)

<

(iv)

<

(i)

<

(iii)

3 (i)

<

(iii)

<

(ii)

<

(iv)

4 (iii)

<

(i)

<

(iv)

<

(ii)

Explanation:

: According to Aufbau's principle the filling of electrons in Various subshells of an atom takes place in the increasing under of energy starting with lowest most. According to the Bohr Bury rule i.e $(n + 1)$ Sum rule, the sub-shell with the lowest value of $(n + l)$ if filled first. If the values for $(n + 1)$ are equal, the one with the smaller value of $n$ is filled first.
{|l|l|l|c|}
| | {$$} | {c|}{ $l$ } | $(+ l)$ |
|---|---|---|---|---|
|i. | 4 | 1 | 5 |
|ii. | 4 | 0 | 4 |
|iii. | 3 | 2 | 5 |
|iv. | 3 | 1 | 4 |
|
The correct order is iv $<$ ii $<$ iii $< i$

J and K CET-(2003)

Structure of Atom

239061 The electrons identified by quantum numbers $n$ and l, (i) $n = 4, l = 1$ (ii) $n = 4, l = 0$ (iii) $n = 3, l =$ 2 and (iv) $n = 3, 1 = 1$ can be placed in order of increasing energy as
#[Qdiff: Easy, QCat: Theory Based, examname: Thus, Hence, |---|, |
,
, {|c|c|c|c|}
, J and K CET-(2011)
, | { Ans. (c): $Extra close brace or missing open brace$ | $l$ | $l$ sub orbit | $+ l$ |, |4 | 1 | $4$ | 5 |, |4 | 0 | $4$ | 4 |, |3 | 2 | $3$ | 5 |, |3 | 1 | $3$ | 4 |, Higher the value of $(n + l)$ , higher the energy if $(n + l)$ are same, sub orbit with lower value of $n$ has lower energy.
, $3 p < 4$ s $< 3 d < 4 p$
, correct order is (iv) $<$ (ii) $<$ (iii) $<$ (i)
, 559. Out of the following which is the correct set of quantum numbers for outermost electron of potassium ( $Z = 19)$ ?
, (b) $4 2 0 0 - 1 / 2$
, (c) $4 1 0 + 1 / 2$
, (d) $4 0 0 - 1 / 2$
, J and K CET-(2010)]#

1 (i)

<

(ii)

<

(iii)

<

(iv)

2 (iv)

<

(iii)

<

(ii)

<

(i)

3 (iv)

<

(ii)

<

(iii)

<

(i)

4 (iv)

<

(i)

<

(ii)

<

(iii)

Explanation:

: Ans. (d) : $K (z = 19) : [Ar]^{18} 4 s^{1}$
Outermost electron :4s $s^{1}$
$n = 4, l = 0, m = 0, s = + \frac{1}{2}$ or $\frac{- 1}{2}$

Structure of Atom

239087 The number of angular and radial nodes in $3 p$ orbital respectively are
#[Qdiff: Easy, QCat: Theory Based, examname: Kerala-CEE-29.08.2021
, Karnataka-CET-2021]#

1 3,1

2 1,1

3 2,1

4 2,3

Explanation:

: For angular node $= ℓ$ and Radial node $= n - ℓ - 1$ Where, $n =$ Principle quantum no. $ℓ =$ Azimuthal quantum no.
For $3 p$ orbitals the value of $ℓ$ for $p$ -orbital is 1
$∴$ No. of angular node $(ℓ) = 1$
and No. of radial nodes $= n - ℓ - 1 = 3 - 1 - 1 = 1$

Structure of Atom

239076 If magnetic quantum number of a given atom represented by 3 , then what will be its principal quantum number?

1 2

2 3

3 4

4 5

Explanation:

: If the magnetic quantum number of a given atom is represented by -3 , then its principal quantum number will be 4
For a given value of $l$
$\begin{aligned} m = - l \dots \dots \dots . \dots \dots + l when \\ m = - 3, l = 3 \end{aligned}$
For given value of $n, l$
Can have values from 0 to $n - 1$ when $l = 3, n = 4$ , So that
$n = - 1, - 4 - 1 = 3$

JIPMER-2006

Structure of Atom

239065 The electrons identified by quantum numbers
(i) $n = 4, 1 = 1$
(ii) $n = 4, 1 = 0$
(iii) $n = 3, 1 = 2$
(iv) $n = 2, 1 = 1$
Can be placed in order of increasing energy from the lowest to highest as

1 (iv)

<

(ii)

<

(iii)

<

(i)

2 (ii)

<

(iv)

<

(i)

<

(iii)

3 (i)

<

(iii)

<

(ii)

<

(iv)

4 (iii)

<

(i)

<

(iv)

<

(ii)

Explanation:

: According to Aufbau's principle the filling of electrons in Various subshells of an atom takes place in the increasing under of energy starting with lowest most. According to the Bohr Bury rule i.e $(n + 1)$ Sum rule, the sub-shell with the lowest value of $(n + l)$ if filled first. If the values for $(n + 1)$ are equal, the one with the smaller value of $n$ is filled first.
{|l|l|l|c|}
| | {$$} | {c|}{ $l$ } | $(+ l)$ |
|---|---|---|---|---|
|i. | 4 | 1 | 5 |
|ii. | 4 | 0 | 4 |
|iii. | 3 | 2 | 5 |
|iv. | 3 | 1 | 4 |
|
The correct order is iv $<$ ii $<$ iii $< i$

J and K CET-(2003)

Structure of Atom

239061 The electrons identified by quantum numbers $n$ and l, (i) $n = 4, l = 1$ (ii) $n = 4, l = 0$ (iii) $n = 3, l =$ 2 and (iv) $n = 3, 1 = 1$ can be placed in order of increasing energy as
#[Qdiff: Easy, QCat: Theory Based, examname: Thus, Hence, |---|, |
,
, {|c|c|c|c|}
, J and K CET-(2011)
, | { Ans. (c): $Extra close brace or missing open brace$ | $l$ | $l$ sub orbit | $+ l$ |, |4 | 1 | $4$ | 5 |, |4 | 0 | $4$ | 4 |, |3 | 2 | $3$ | 5 |, |3 | 1 | $3$ | 4 |, Higher the value of $(n + l)$ , higher the energy if $(n + l)$ are same, sub orbit with lower value of $n$ has lower energy.
, $3 p < 4$ s $< 3 d < 4 p$
, correct order is (iv) $<$ (ii) $<$ (iii) $<$ (i)
, 559. Out of the following which is the correct set of quantum numbers for outermost electron of potassium ( $Z = 19)$ ?
, (b) $4 2 0 0 - 1 / 2$
, (c) $4 1 0 + 1 / 2$
, (d) $4 0 0 - 1 / 2$
, J and K CET-(2010)]#

1 (i)

<

(ii)

<

(iii)

<

(iv)

2 (iv)

<

(iii)

<

(ii)

<

(i)

3 (iv)

<

(ii)

<

(iii)

<

(i)

4 (iv)

<

(i)

<

(ii)

<

(iii)

Explanation:

: Ans. (d) : $K (z = 19) : [Ar]^{18} 4 s^{1}$
Outermost electron :4s $s^{1}$
$n = 4, l = 0, m = 0, s = + \frac{1}{2}$ or $\frac{- 1}{2}$

Structure of Atom

239087 The number of angular and radial nodes in $3 p$ orbital respectively are
#[Qdiff: Easy, QCat: Theory Based, examname: Kerala-CEE-29.08.2021
, Karnataka-CET-2021]#

1 3,1

2 1,1

3 2,1

4 2,3

Explanation:

: For angular node $= ℓ$ and Radial node $= n - ℓ - 1$ Where, $n =$ Principle quantum no. $ℓ =$ Azimuthal quantum no.
For $3 p$ orbitals the value of $ℓ$ for $p$ -orbital is 1
$∴$ No. of angular node $(ℓ) = 1$
and No. of radial nodes $= n - ℓ - 1 = 3 - 1 - 1 = 1$

Structure of Atom

239076 If magnetic quantum number of a given atom represented by 3 , then what will be its principal quantum number?

1 2

2 3

3 4

4 5

Explanation:

: If the magnetic quantum number of a given atom is represented by -3 , then its principal quantum number will be 4
For a given value of $l$
$\begin{aligned} m = - l \dots \dots \dots . \dots \dots + l when \\ m = - 3, l = 3 \end{aligned}$
For given value of $n, l$
Can have values from 0 to $n - 1$ when $l = 3, n = 4$ , So that
$n = - 1, - 4 - 1 = 3$

JIPMER-2006

Structure of Atom

239065 The electrons identified by quantum numbers
(i) $n = 4, 1 = 1$
(ii) $n = 4, 1 = 0$
(iii) $n = 3, 1 = 2$
(iv) $n = 2, 1 = 1$
Can be placed in order of increasing energy from the lowest to highest as

1 (iv)

<

(ii)

<

(iii)

<

(i)

2 (ii)

<

(iv)

<

(i)

<

(iii)

3 (i)

<

(iii)

<

(ii)

<

(iv)

4 (iii)

<

(i)

<

(iv)

<

(ii)

Explanation:

: According to Aufbau's principle the filling of electrons in Various subshells of an atom takes place in the increasing under of energy starting with lowest most. According to the Bohr Bury rule i.e $(n + 1)$ Sum rule, the sub-shell with the lowest value of $(n + l)$ if filled first. If the values for $(n + 1)$ are equal, the one with the smaller value of $n$ is filled first.
{|l|l|l|c|}
| | {$$} | {c|}{ $l$ } | $(+ l)$ |
|---|---|---|---|---|
|i. | 4 | 1 | 5 |
|ii. | 4 | 0 | 4 |
|iii. | 3 | 2 | 5 |
|iv. | 3 | 1 | 4 |
|
The correct order is iv $<$ ii $<$ iii $< i$

J and K CET-(2003)

Structure of Atom

239061 The electrons identified by quantum numbers $n$ and l, (i) $n = 4, l = 1$ (ii) $n = 4, l = 0$ (iii) $n = 3, l =$ 2 and (iv) $n = 3, 1 = 1$ can be placed in order of increasing energy as
#[Qdiff: Easy, QCat: Theory Based, examname: Thus, Hence, |---|, |
,
, {|c|c|c|c|}
, J and K CET-(2011)
, | { Ans. (c): $Extra close brace or missing open brace$ | $l$ | $l$ sub orbit | $+ l$ |, |4 | 1 | $4$ | 5 |, |4 | 0 | $4$ | 4 |, |3 | 2 | $3$ | 5 |, |3 | 1 | $3$ | 4 |, Higher the value of $(n + l)$ , higher the energy if $(n + l)$ are same, sub orbit with lower value of $n$ has lower energy.
, $3 p < 4$ s $< 3 d < 4 p$
, correct order is (iv) $<$ (ii) $<$ (iii) $<$ (i)
, 559. Out of the following which is the correct set of quantum numbers for outermost electron of potassium ( $Z = 19)$ ?
, (b) $4 2 0 0 - 1 / 2$
, (c) $4 1 0 + 1 / 2$
, (d) $4 0 0 - 1 / 2$
, J and K CET-(2010)]#

1 (i)

<

(ii)

<

(iii)

<

(iv)

2 (iv)

<

(iii)

<

(ii)

<

(i)

3 (iv)

<

(ii)

<

(iii)

<

(i)

4 (iv)

<

(i)

<

(ii)

<

(iii)

Explanation:

: Ans. (d) : $K (z = 19) : [Ar]^{18} 4 s^{1}$
Outermost electron :4s $s^{1}$
$n = 4, l = 0, m = 0, s = + \frac{1}{2}$ or $\frac{- 1}{2}$

Structure of Atom

239087 The number of angular and radial nodes in $3 p$ orbital respectively are
#[Qdiff: Easy, QCat: Theory Based, examname: Kerala-CEE-29.08.2021
, Karnataka-CET-2021]#

1 3,1

2 1,1

3 2,1

4 2,3

Explanation:

: For angular node $= ℓ$ and Radial node $= n - ℓ - 1$ Where, $n =$ Principle quantum no. $ℓ =$ Azimuthal quantum no.
For $3 p$ orbitals the value of $ℓ$ for $p$ -orbital is 1
$∴$ No. of angular node $(ℓ) = 1$
and No. of radial nodes $= n - ℓ - 1 = 3 - 1 - 1 = 1$

Structure of Atom

239076 If magnetic quantum number of a given atom represented by 3 , then what will be its principal quantum number?

1 2

2 3

3 4

4 5

Explanation:

: If the magnetic quantum number of a given atom is represented by -3 , then its principal quantum number will be 4
For a given value of $l$
$\begin{aligned} m = - l \dots \dots \dots . \dots \dots + l when \\ m = - 3, l = 3 \end{aligned}$
For given value of $n, l$
Can have values from 0 to $n - 1$ when $l = 3, n = 4$ , So that
$n = - 1, - 4 - 1 = 3$

JIPMER-2006

Structure of Atom

239065 The electrons identified by quantum numbers
(i) $n = 4, 1 = 1$
(ii) $n = 4, 1 = 0$
(iii) $n = 3, 1 = 2$
(iv) $n = 2, 1 = 1$
Can be placed in order of increasing energy from the lowest to highest as

1 (iv)

<

(ii)

<

(iii)

<

(i)

2 (ii)

<

(iv)

<

(i)

<

(iii)

3 (i)

<

(iii)

<

(ii)

<

(iv)

4 (iii)

<

(i)

<

(iv)

<

(ii)

Explanation:

: According to Aufbau's principle the filling of electrons in Various subshells of an atom takes place in the increasing under of energy starting with lowest most. According to the Bohr Bury rule i.e $(n + 1)$ Sum rule, the sub-shell with the lowest value of $(n + l)$ if filled first. If the values for $(n + 1)$ are equal, the one with the smaller value of $n$ is filled first.
{|l|l|l|c|}
| | {$$} | {c|}{ $l$ } | $(+ l)$ |
|---|---|---|---|---|
|i. | 4 | 1 | 5 |
|ii. | 4 | 0 | 4 |
|iii. | 3 | 2 | 5 |
|iv. | 3 | 1 | 4 |
|
The correct order is iv $<$ ii $<$ iii $< i$

J and K CET-(2003)

Structure of Atom

239061 The electrons identified by quantum numbers $n$ and l, (i) $n = 4, l = 1$ (ii) $n = 4, l = 0$ (iii) $n = 3, l =$ 2 and (iv) $n = 3, 1 = 1$ can be placed in order of increasing energy as
#[Qdiff: Easy, QCat: Theory Based, examname: Thus, Hence, |---|, |
,
, {|c|c|c|c|}
, J and K CET-(2011)
, | { Ans. (c): $Extra close brace or missing open brace$ | $l$ | $l$ sub orbit | $+ l$ |, |4 | 1 | $4$ | 5 |, |4 | 0 | $4$ | 4 |, |3 | 2 | $3$ | 5 |, |3 | 1 | $3$ | 4 |, Higher the value of $(n + l)$ , higher the energy if $(n + l)$ are same, sub orbit with lower value of $n$ has lower energy.
, $3 p < 4$ s $< 3 d < 4 p$
, correct order is (iv) $<$ (ii) $<$ (iii) $<$ (i)
, 559. Out of the following which is the correct set of quantum numbers for outermost electron of potassium ( $Z = 19)$ ?
, (b) $4 2 0 0 - 1 / 2$
, (c) $4 1 0 + 1 / 2$
, (d) $4 0 0 - 1 / 2$
, J and K CET-(2010)]#

1 (i)

<

(ii)

<

(iii)

<

(iv)

2 (iv)

<

(iii)

<

(ii)

<

(i)

3 (iv)

<

(ii)

<

(iii)

<

(i)

4 (iv)

<

(i)

<

(ii)

<

(iii)

Explanation:

: Ans. (d) : $K (z = 19) : [Ar]^{18} 4 s^{1}$
Outermost electron :4s $s^{1}$
$n = 4, l = 0, m = 0, s = + \frac{1}{2}$ or $\frac{- 1}{2}$

Structure of Atom

239087 The number of angular and radial nodes in $3 p$ orbital respectively are
#[Qdiff: Easy, QCat: Theory Based, examname: Kerala-CEE-29.08.2021
, Karnataka-CET-2021]#

1 3,1

2 1,1

3 2,1

4 2,3

Explanation:

: For angular node $= ℓ$ and Radial node $= n - ℓ - 1$ Where, $n =$ Principle quantum no. $ℓ =$ Azimuthal quantum no.
For $3 p$ orbitals the value of $ℓ$ for $p$ -orbital is 1
$∴$ No. of angular node $(ℓ) = 1$
and No. of radial nodes $= n - ℓ - 1 = 3 - 1 - 1 = 1$

Structure of Atom

239076 If magnetic quantum number of a given atom represented by 3 , then what will be its principal quantum number?

1 2

2 3

3 4

4 5

Explanation:

: If the magnetic quantum number of a given atom is represented by -3 , then its principal quantum number will be 4
For a given value of $l$
$\begin{aligned} m = - l \dots \dots \dots . \dots \dots + l when \\ m = - 3, l = 3 \end{aligned}$
For given value of $n, l$
Can have values from 0 to $n - 1$ when $l = 3, n = 4$ , So that
$n = - 1, - 4 - 1 = 3$

JIPMER-2006

Question Bank Series

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