228896
$12 \mathrm{~g}$ of $\mathrm{Mg}$ with excess of $\mathrm{HCl}$ at NTP gives
1 $11.2 \mathrm{dm}^3$ of $\mathrm{H}_2$
2 $22.4 \mathrm{dm}^3$ of $\mathrm{H}_2$
3 $5.6 \mathrm{dm}^3$ of $\mathrm{H}_2$
4 $15.6 \mathrm{dm}^3$ of $\mathrm{H}_2$
Explanation:
$\mathrm{Mg}+2 \mathrm{HCl} \rightarrow \mathrm{MgCl}_2+\mathrm{H}_2$ Thus, $12 \mathrm{~g}$ of $\mathrm{Mg}$ produces $=1 \mathrm{~g}$ or $11.2 \mathrm{dm}^3 \mathrm{H}_2$ at NTP.
COMEDK-2011
Some Basic Concepts of Chemistry
228900
During electrolysis of water the volume of $\mathrm{O}_2$ liberated is $2.24 \mathrm{dm}^3$. The volume of hydrogen liberated, under same conditions will be
1 $2.24 \mathrm{dm}^3$
2 $1.12 \mathrm{dm}^3$
3 $4.48 \mathrm{dm}^3$
4 $0.56 \mathrm{dm}^3$
Explanation:
$\underset{2 \mathrm{Vol} .}{2 \mathrm{H}_2 \mathrm{O}} \stackrel{\text { Electrolysis }}{\longrightarrow} \underset{2 \mathrm{Vol} .}{2 \mathrm{H}_2}+\underset{1 \mathrm{Vol} .}{\mathrm{O}_2}$The volume of hydrogen liberated is twice that of the volume of oxygen liberated. When $2.24 \mathrm{dm}^3$ of oxygen is liberated the volume of hydrogen liberated will be $2 \times$ $2.24 \mathrm{dm}^3$ or $4.48 \mathrm{dm}^3$.
AIIMS-2008
Some Basic Concepts of Chemistry
228901
The stoichiometry of the following reaction is $\mathrm{K}_2 \mathrm{~S}_2 \mathrm{O}_8(\mathrm{aq})+2 \mathrm{KI}(\mathrm{aq}) \rightarrow 2 \mathrm{~K}_2 \mathrm{SO}_4(\mathrm{aq})+\mathrm{I}_2(\mathrm{aq})$
1 $2: 2$
2 $1: 1$
3 $1: 2$
4 $2: 1$
Explanation:
$\mathrm{K}_2 \mathrm{~S}_2 \mathrm{O}_8$ (aq) $+2 \mathrm{KI}$ (aq) $\rightarrow 2 \mathrm{~K}_2 \mathrm{SO}_4$ (aq) + $\mathrm{I}_2(\mathrm{aq})$ In the reaction one mole of $\mathrm{K}_2 \mathrm{~S}_2 \mathrm{O}_8$ reacts with 2 moles of KI, so the stoichiometry of this reaction is $1: 2$.
J and K CET-(2008)
Some Basic Concepts of Chemistry
228907
3 moles of ethanol reacts with one mole of phosphorus tribromide to form 3 moles of bromo-ethane and one mole of $X$. Which of the following is $\mathrm{X}$ ?
1 $\mathrm{H}_3 \mathrm{PO}_4$
2 $\mathrm{H}_3 \mathrm{PO}_2$
3 $\mathrm{HPO}_3$
4 $\mathrm{H}_3 \mathrm{PO}_3$
Explanation:
3 moles of ethanol reacts with 1 mole of phosphorous tribromide to form 3 moles of bromoethane and 1 mole of arthophosphorus acid $\left(\mathrm{H}_3 \mathrm{PO}_3\right)$ $3 \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}+\mathrm{PBr}_3 \rightarrow 3 \mathrm{C}_2 \mathrm{H}_5 \mathrm{Br}+\mathrm{H}_3 \mathrm{PO}_3$
228896
$12 \mathrm{~g}$ of $\mathrm{Mg}$ with excess of $\mathrm{HCl}$ at NTP gives
1 $11.2 \mathrm{dm}^3$ of $\mathrm{H}_2$
2 $22.4 \mathrm{dm}^3$ of $\mathrm{H}_2$
3 $5.6 \mathrm{dm}^3$ of $\mathrm{H}_2$
4 $15.6 \mathrm{dm}^3$ of $\mathrm{H}_2$
Explanation:
$\mathrm{Mg}+2 \mathrm{HCl} \rightarrow \mathrm{MgCl}_2+\mathrm{H}_2$ Thus, $12 \mathrm{~g}$ of $\mathrm{Mg}$ produces $=1 \mathrm{~g}$ or $11.2 \mathrm{dm}^3 \mathrm{H}_2$ at NTP.
COMEDK-2011
Some Basic Concepts of Chemistry
228900
During electrolysis of water the volume of $\mathrm{O}_2$ liberated is $2.24 \mathrm{dm}^3$. The volume of hydrogen liberated, under same conditions will be
1 $2.24 \mathrm{dm}^3$
2 $1.12 \mathrm{dm}^3$
3 $4.48 \mathrm{dm}^3$
4 $0.56 \mathrm{dm}^3$
Explanation:
$\underset{2 \mathrm{Vol} .}{2 \mathrm{H}_2 \mathrm{O}} \stackrel{\text { Electrolysis }}{\longrightarrow} \underset{2 \mathrm{Vol} .}{2 \mathrm{H}_2}+\underset{1 \mathrm{Vol} .}{\mathrm{O}_2}$The volume of hydrogen liberated is twice that of the volume of oxygen liberated. When $2.24 \mathrm{dm}^3$ of oxygen is liberated the volume of hydrogen liberated will be $2 \times$ $2.24 \mathrm{dm}^3$ or $4.48 \mathrm{dm}^3$.
AIIMS-2008
Some Basic Concepts of Chemistry
228901
The stoichiometry of the following reaction is $\mathrm{K}_2 \mathrm{~S}_2 \mathrm{O}_8(\mathrm{aq})+2 \mathrm{KI}(\mathrm{aq}) \rightarrow 2 \mathrm{~K}_2 \mathrm{SO}_4(\mathrm{aq})+\mathrm{I}_2(\mathrm{aq})$
1 $2: 2$
2 $1: 1$
3 $1: 2$
4 $2: 1$
Explanation:
$\mathrm{K}_2 \mathrm{~S}_2 \mathrm{O}_8$ (aq) $+2 \mathrm{KI}$ (aq) $\rightarrow 2 \mathrm{~K}_2 \mathrm{SO}_4$ (aq) + $\mathrm{I}_2(\mathrm{aq})$ In the reaction one mole of $\mathrm{K}_2 \mathrm{~S}_2 \mathrm{O}_8$ reacts with 2 moles of KI, so the stoichiometry of this reaction is $1: 2$.
J and K CET-(2008)
Some Basic Concepts of Chemistry
228907
3 moles of ethanol reacts with one mole of phosphorus tribromide to form 3 moles of bromo-ethane and one mole of $X$. Which of the following is $\mathrm{X}$ ?
1 $\mathrm{H}_3 \mathrm{PO}_4$
2 $\mathrm{H}_3 \mathrm{PO}_2$
3 $\mathrm{HPO}_3$
4 $\mathrm{H}_3 \mathrm{PO}_3$
Explanation:
3 moles of ethanol reacts with 1 mole of phosphorous tribromide to form 3 moles of bromoethane and 1 mole of arthophosphorus acid $\left(\mathrm{H}_3 \mathrm{PO}_3\right)$ $3 \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}+\mathrm{PBr}_3 \rightarrow 3 \mathrm{C}_2 \mathrm{H}_5 \mathrm{Br}+\mathrm{H}_3 \mathrm{PO}_3$
228896
$12 \mathrm{~g}$ of $\mathrm{Mg}$ with excess of $\mathrm{HCl}$ at NTP gives
1 $11.2 \mathrm{dm}^3$ of $\mathrm{H}_2$
2 $22.4 \mathrm{dm}^3$ of $\mathrm{H}_2$
3 $5.6 \mathrm{dm}^3$ of $\mathrm{H}_2$
4 $15.6 \mathrm{dm}^3$ of $\mathrm{H}_2$
Explanation:
$\mathrm{Mg}+2 \mathrm{HCl} \rightarrow \mathrm{MgCl}_2+\mathrm{H}_2$ Thus, $12 \mathrm{~g}$ of $\mathrm{Mg}$ produces $=1 \mathrm{~g}$ or $11.2 \mathrm{dm}^3 \mathrm{H}_2$ at NTP.
COMEDK-2011
Some Basic Concepts of Chemistry
228900
During electrolysis of water the volume of $\mathrm{O}_2$ liberated is $2.24 \mathrm{dm}^3$. The volume of hydrogen liberated, under same conditions will be
1 $2.24 \mathrm{dm}^3$
2 $1.12 \mathrm{dm}^3$
3 $4.48 \mathrm{dm}^3$
4 $0.56 \mathrm{dm}^3$
Explanation:
$\underset{2 \mathrm{Vol} .}{2 \mathrm{H}_2 \mathrm{O}} \stackrel{\text { Electrolysis }}{\longrightarrow} \underset{2 \mathrm{Vol} .}{2 \mathrm{H}_2}+\underset{1 \mathrm{Vol} .}{\mathrm{O}_2}$The volume of hydrogen liberated is twice that of the volume of oxygen liberated. When $2.24 \mathrm{dm}^3$ of oxygen is liberated the volume of hydrogen liberated will be $2 \times$ $2.24 \mathrm{dm}^3$ or $4.48 \mathrm{dm}^3$.
AIIMS-2008
Some Basic Concepts of Chemistry
228901
The stoichiometry of the following reaction is $\mathrm{K}_2 \mathrm{~S}_2 \mathrm{O}_8(\mathrm{aq})+2 \mathrm{KI}(\mathrm{aq}) \rightarrow 2 \mathrm{~K}_2 \mathrm{SO}_4(\mathrm{aq})+\mathrm{I}_2(\mathrm{aq})$
1 $2: 2$
2 $1: 1$
3 $1: 2$
4 $2: 1$
Explanation:
$\mathrm{K}_2 \mathrm{~S}_2 \mathrm{O}_8$ (aq) $+2 \mathrm{KI}$ (aq) $\rightarrow 2 \mathrm{~K}_2 \mathrm{SO}_4$ (aq) + $\mathrm{I}_2(\mathrm{aq})$ In the reaction one mole of $\mathrm{K}_2 \mathrm{~S}_2 \mathrm{O}_8$ reacts with 2 moles of KI, so the stoichiometry of this reaction is $1: 2$.
J and K CET-(2008)
Some Basic Concepts of Chemistry
228907
3 moles of ethanol reacts with one mole of phosphorus tribromide to form 3 moles of bromo-ethane and one mole of $X$. Which of the following is $\mathrm{X}$ ?
1 $\mathrm{H}_3 \mathrm{PO}_4$
2 $\mathrm{H}_3 \mathrm{PO}_2$
3 $\mathrm{HPO}_3$
4 $\mathrm{H}_3 \mathrm{PO}_3$
Explanation:
3 moles of ethanol reacts with 1 mole of phosphorous tribromide to form 3 moles of bromoethane and 1 mole of arthophosphorus acid $\left(\mathrm{H}_3 \mathrm{PO}_3\right)$ $3 \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}+\mathrm{PBr}_3 \rightarrow 3 \mathrm{C}_2 \mathrm{H}_5 \mathrm{Br}+\mathrm{H}_3 \mathrm{PO}_3$
228896
$12 \mathrm{~g}$ of $\mathrm{Mg}$ with excess of $\mathrm{HCl}$ at NTP gives
1 $11.2 \mathrm{dm}^3$ of $\mathrm{H}_2$
2 $22.4 \mathrm{dm}^3$ of $\mathrm{H}_2$
3 $5.6 \mathrm{dm}^3$ of $\mathrm{H}_2$
4 $15.6 \mathrm{dm}^3$ of $\mathrm{H}_2$
Explanation:
$\mathrm{Mg}+2 \mathrm{HCl} \rightarrow \mathrm{MgCl}_2+\mathrm{H}_2$ Thus, $12 \mathrm{~g}$ of $\mathrm{Mg}$ produces $=1 \mathrm{~g}$ or $11.2 \mathrm{dm}^3 \mathrm{H}_2$ at NTP.
COMEDK-2011
Some Basic Concepts of Chemistry
228900
During electrolysis of water the volume of $\mathrm{O}_2$ liberated is $2.24 \mathrm{dm}^3$. The volume of hydrogen liberated, under same conditions will be
1 $2.24 \mathrm{dm}^3$
2 $1.12 \mathrm{dm}^3$
3 $4.48 \mathrm{dm}^3$
4 $0.56 \mathrm{dm}^3$
Explanation:
$\underset{2 \mathrm{Vol} .}{2 \mathrm{H}_2 \mathrm{O}} \stackrel{\text { Electrolysis }}{\longrightarrow} \underset{2 \mathrm{Vol} .}{2 \mathrm{H}_2}+\underset{1 \mathrm{Vol} .}{\mathrm{O}_2}$The volume of hydrogen liberated is twice that of the volume of oxygen liberated. When $2.24 \mathrm{dm}^3$ of oxygen is liberated the volume of hydrogen liberated will be $2 \times$ $2.24 \mathrm{dm}^3$ or $4.48 \mathrm{dm}^3$.
AIIMS-2008
Some Basic Concepts of Chemistry
228901
The stoichiometry of the following reaction is $\mathrm{K}_2 \mathrm{~S}_2 \mathrm{O}_8(\mathrm{aq})+2 \mathrm{KI}(\mathrm{aq}) \rightarrow 2 \mathrm{~K}_2 \mathrm{SO}_4(\mathrm{aq})+\mathrm{I}_2(\mathrm{aq})$
1 $2: 2$
2 $1: 1$
3 $1: 2$
4 $2: 1$
Explanation:
$\mathrm{K}_2 \mathrm{~S}_2 \mathrm{O}_8$ (aq) $+2 \mathrm{KI}$ (aq) $\rightarrow 2 \mathrm{~K}_2 \mathrm{SO}_4$ (aq) + $\mathrm{I}_2(\mathrm{aq})$ In the reaction one mole of $\mathrm{K}_2 \mathrm{~S}_2 \mathrm{O}_8$ reacts with 2 moles of KI, so the stoichiometry of this reaction is $1: 2$.
J and K CET-(2008)
Some Basic Concepts of Chemistry
228907
3 moles of ethanol reacts with one mole of phosphorus tribromide to form 3 moles of bromo-ethane and one mole of $X$. Which of the following is $\mathrm{X}$ ?
1 $\mathrm{H}_3 \mathrm{PO}_4$
2 $\mathrm{H}_3 \mathrm{PO}_2$
3 $\mathrm{HPO}_3$
4 $\mathrm{H}_3 \mathrm{PO}_3$
Explanation:
3 moles of ethanol reacts with 1 mole of phosphorous tribromide to form 3 moles of bromoethane and 1 mole of arthophosphorus acid $\left(\mathrm{H}_3 \mathrm{PO}_3\right)$ $3 \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}+\mathrm{PBr}_3 \rightarrow 3 \mathrm{C}_2 \mathrm{H}_5 \mathrm{Br}+\mathrm{H}_3 \mathrm{PO}_3$
