QBManager

Molecular Basis of Inheritance and

166113 The central dogma is not applicable in the case of

1 retroviruses

2 all prokaryotes

3 all animal viruses

4 all plant viruses

Manipal-2011

Molecular Basis of Inheritance and

166115 Total number of complete spirals occurring in a segment of DNA having 100 nucleotides will be

1 5

2 6

3 3

4 4

Explanation:

Number of nucleotide bases of a spiral of dsDNA molecule is twenty (10 base pairs)
So, 1 spiral $= 20$ nucleotide
5 spiral $= 20 \times 5$
5 Spiral $= 100$ nucleotide

MHT CET 5.10.2020 Shift-I

Molecular Basis of Inheritance and

166117 Which one of the following is NOT needed to construct solenoid fibre?

1 Nucleosome

2 DNA molecule

3 RNA molecule

4 Basic proteins histones

Explanation:

The solenoid model represents the organization of the nucleosome with the $30 nm$ wide chromatin fibre. The term solenoid itself defines the winding of the DNA helix. In eukaryotes, the DNA is compressed into chromatin fibre after the association of DNA-linking histone proteins.
Nucleosome and Solenoid Model

MHT CET 5.10.2020 Shift-I

Molecular Basis of Inheritance and

166119 If the total amount of adenine and thymine in a double-stranded DNA is $45 %$ , the amount of guanine in this DNA will be

1

22.5 %

2

27.5 %

3

45 %

4

55 %

Explanation:

The total amount of $T$ and $A = 45 %$ then, total amount of $G$ and $C$ will be equal to $100 % - 45 % =$ $55 %$
Also, $% G = % C$ , Therefore $% G = % C$ $= \frac{55 %}{2} = 27.5 %$ so, the percentage of guanine in DNA will be equal to $27.5 %$ .

DUMET-2010

Molecular Basis of Inheritance and

166113 The central dogma is not applicable in the case of

1 retroviruses

2 all prokaryotes

3 all animal viruses

4 all plant viruses

Manipal-2011

Molecular Basis of Inheritance and

166115 Total number of complete spirals occurring in a segment of DNA having 100 nucleotides will be

1 5

2 6

3 3

4 4

Explanation:

Number of nucleotide bases of a spiral of dsDNA molecule is twenty (10 base pairs)
So, 1 spiral $= 20$ nucleotide
5 spiral $= 20 \times 5$
5 Spiral $= 100$ nucleotide

MHT CET 5.10.2020 Shift-I

Molecular Basis of Inheritance and

166117 Which one of the following is NOT needed to construct solenoid fibre?

1 Nucleosome

2 DNA molecule

3 RNA molecule

4 Basic proteins histones

Explanation:

The solenoid model represents the organization of the nucleosome with the $30 nm$ wide chromatin fibre. The term solenoid itself defines the winding of the DNA helix. In eukaryotes, the DNA is compressed into chromatin fibre after the association of DNA-linking histone proteins.
Nucleosome and Solenoid Model

MHT CET 5.10.2020 Shift-I

Molecular Basis of Inheritance and

166119 If the total amount of adenine and thymine in a double-stranded DNA is $45 %$ , the amount of guanine in this DNA will be

1

22.5 %

2

27.5 %

3

45 %

4

55 %

Explanation:

The total amount of $T$ and $A = 45 %$ then, total amount of $G$ and $C$ will be equal to $100 % - 45 % =$ $55 %$
Also, $% G = % C$ , Therefore $% G = % C$ $= \frac{55 %}{2} = 27.5 %$ so, the percentage of guanine in DNA will be equal to $27.5 %$ .

DUMET-2010

Molecular Basis of Inheritance and

166113 The central dogma is not applicable in the case of

1 retroviruses

2 all prokaryotes

3 all animal viruses

4 all plant viruses

Manipal-2011

Molecular Basis of Inheritance and

166115 Total number of complete spirals occurring in a segment of DNA having 100 nucleotides will be

1 5

2 6

3 3

4 4

Explanation:

Number of nucleotide bases of a spiral of dsDNA molecule is twenty (10 base pairs)
So, 1 spiral $= 20$ nucleotide
5 spiral $= 20 \times 5$
5 Spiral $= 100$ nucleotide

MHT CET 5.10.2020 Shift-I

Molecular Basis of Inheritance and

166117 Which one of the following is NOT needed to construct solenoid fibre?

1 Nucleosome

2 DNA molecule

3 RNA molecule

4 Basic proteins histones

Explanation:

The solenoid model represents the organization of the nucleosome with the $30 nm$ wide chromatin fibre. The term solenoid itself defines the winding of the DNA helix. In eukaryotes, the DNA is compressed into chromatin fibre after the association of DNA-linking histone proteins.
Nucleosome and Solenoid Model

MHT CET 5.10.2020 Shift-I

Molecular Basis of Inheritance and

166119 If the total amount of adenine and thymine in a double-stranded DNA is $45 %$ , the amount of guanine in this DNA will be

1

22.5 %

2

27.5 %

3

45 %

4

55 %

Explanation:

The total amount of $T$ and $A = 45 %$ then, total amount of $G$ and $C$ will be equal to $100 % - 45 % =$ $55 %$
Also, $% G = % C$ , Therefore $% G = % C$ $= \frac{55 %}{2} = 27.5 %$ so, the percentage of guanine in DNA will be equal to $27.5 %$ .

DUMET-2010

Molecular Basis of Inheritance and

166113 The central dogma is not applicable in the case of

1 retroviruses

2 all prokaryotes

3 all animal viruses

4 all plant viruses

Manipal-2011

Molecular Basis of Inheritance and

166115 Total number of complete spirals occurring in a segment of DNA having 100 nucleotides will be

1 5

2 6

3 3

4 4

Explanation:

Number of nucleotide bases of a spiral of dsDNA molecule is twenty (10 base pairs)
So, 1 spiral $= 20$ nucleotide
5 spiral $= 20 \times 5$
5 Spiral $= 100$ nucleotide

MHT CET 5.10.2020 Shift-I

Molecular Basis of Inheritance and

166117 Which one of the following is NOT needed to construct solenoid fibre?

1 Nucleosome

2 DNA molecule

3 RNA molecule

4 Basic proteins histones

Explanation:

The solenoid model represents the organization of the nucleosome with the $30 nm$ wide chromatin fibre. The term solenoid itself defines the winding of the DNA helix. In eukaryotes, the DNA is compressed into chromatin fibre after the association of DNA-linking histone proteins.
Nucleosome and Solenoid Model

MHT CET 5.10.2020 Shift-I

Molecular Basis of Inheritance and

166119 If the total amount of adenine and thymine in a double-stranded DNA is $45 %$ , the amount of guanine in this DNA will be

1

22.5 %

2

27.5 %

3

45 %

4

55 %

Explanation:

The total amount of $T$ and $A = 45 %$ then, total amount of $G$ and $C$ will be equal to $100 % - 45 % =$ $55 %$
Also, $% G = % C$ , Therefore $% G = % C$ $= \frac{55 %}{2} = 27.5 %$ so, the percentage of guanine in DNA will be equal to $27.5 %$ .

DUMET-2010