184754
In a marriage between male with blood group A and female with blood group B, the progeny had either blood group \(A B\) or \(B\). What could be the possible genotype of parents?
: Male with blood group A can have genotype \(\mathrm{I}^{\mathrm{A}} \mathrm{i}\) or \(\mathrm{I}^{\mathrm{A}} \mathrm{I}^{\mathrm{A}}\). - Female with blood group \(\mathbf{B}\) can have genotype \(I^{\mathrm{F}} I^{\mathrm{B}}\) or \(\mathrm{I}_{\mathrm{i}}\)
NEET (Odisha)-2019
Principle of Inheritance and Variation
184758
Of a normal couple, half the sons are haemophiliac while half the daughters are carriers. the gene is located on
1 X-chromosome of father
2 Y-chromosome of father
3 one X-chromosome of mother
4 both the X-chromosomes of mother APMT-1993
Explanation:
: The gene of haemophilia is located on X chromosome. In this case where half the sons are haemophilic and half the daughters are camiers, it is possible only when the gene responsible for haemophilia is located on one X-chromosome of mother.
Principle of Inheritance and Variation
184759
A colour blind mother and normal father would have
1 colour blind sons and normalicarrier daughters
2 colour blind sons and daughters
3 all colour blind
4 all normal APMT-1992
Explanation:
: A colourblind mother and normal father will have colour blind sons and normal/carrier daughters. Colour blind mother \(\times \quad\) Normal father
Principle of Inheritance and Variation
184764
Which of the following is correct match?
1 XO (i) Flat nose,
2 42 AA simian crease syndrome (ii) Webbing of \(+X Y\) neck
3 44 AA (iii) Anaemia, syndrome
4 Klinefelter's \(+\mathrm{XXX}\)
Explanation:
: Sickleceell anaemia is a autosomal linked tecessive trait which gets transmitted from parents to offspring's when both the partners are the carrier for the gene. Carrier Mother \(\mathrm{X} \quad\) Carrier Father
184754
In a marriage between male with blood group A and female with blood group B, the progeny had either blood group \(A B\) or \(B\). What could be the possible genotype of parents?
: Male with blood group A can have genotype \(\mathrm{I}^{\mathrm{A}} \mathrm{i}\) or \(\mathrm{I}^{\mathrm{A}} \mathrm{I}^{\mathrm{A}}\). - Female with blood group \(\mathbf{B}\) can have genotype \(I^{\mathrm{F}} I^{\mathrm{B}}\) or \(\mathrm{I}_{\mathrm{i}}\)
NEET (Odisha)-2019
Principle of Inheritance and Variation
184758
Of a normal couple, half the sons are haemophiliac while half the daughters are carriers. the gene is located on
1 X-chromosome of father
2 Y-chromosome of father
3 one X-chromosome of mother
4 both the X-chromosomes of mother APMT-1993
Explanation:
: The gene of haemophilia is located on X chromosome. In this case where half the sons are haemophilic and half the daughters are camiers, it is possible only when the gene responsible for haemophilia is located on one X-chromosome of mother.
Principle of Inheritance and Variation
184759
A colour blind mother and normal father would have
1 colour blind sons and normalicarrier daughters
2 colour blind sons and daughters
3 all colour blind
4 all normal APMT-1992
Explanation:
: A colourblind mother and normal father will have colour blind sons and normal/carrier daughters. Colour blind mother \(\times \quad\) Normal father
Principle of Inheritance and Variation
184764
Which of the following is correct match?
1 XO (i) Flat nose,
2 42 AA simian crease syndrome (ii) Webbing of \(+X Y\) neck
3 44 AA (iii) Anaemia, syndrome
4 Klinefelter's \(+\mathrm{XXX}\)
Explanation:
: Sickleceell anaemia is a autosomal linked tecessive trait which gets transmitted from parents to offspring's when both the partners are the carrier for the gene. Carrier Mother \(\mathrm{X} \quad\) Carrier Father
184754
In a marriage between male with blood group A and female with blood group B, the progeny had either blood group \(A B\) or \(B\). What could be the possible genotype of parents?
: Male with blood group A can have genotype \(\mathrm{I}^{\mathrm{A}} \mathrm{i}\) or \(\mathrm{I}^{\mathrm{A}} \mathrm{I}^{\mathrm{A}}\). - Female with blood group \(\mathbf{B}\) can have genotype \(I^{\mathrm{F}} I^{\mathrm{B}}\) or \(\mathrm{I}_{\mathrm{i}}\)
NEET (Odisha)-2019
Principle of Inheritance and Variation
184758
Of a normal couple, half the sons are haemophiliac while half the daughters are carriers. the gene is located on
1 X-chromosome of father
2 Y-chromosome of father
3 one X-chromosome of mother
4 both the X-chromosomes of mother APMT-1993
Explanation:
: The gene of haemophilia is located on X chromosome. In this case where half the sons are haemophilic and half the daughters are camiers, it is possible only when the gene responsible for haemophilia is located on one X-chromosome of mother.
Principle of Inheritance and Variation
184759
A colour blind mother and normal father would have
1 colour blind sons and normalicarrier daughters
2 colour blind sons and daughters
3 all colour blind
4 all normal APMT-1992
Explanation:
: A colourblind mother and normal father will have colour blind sons and normal/carrier daughters. Colour blind mother \(\times \quad\) Normal father
Principle of Inheritance and Variation
184764
Which of the following is correct match?
1 XO (i) Flat nose,
2 42 AA simian crease syndrome (ii) Webbing of \(+X Y\) neck
3 44 AA (iii) Anaemia, syndrome
4 Klinefelter's \(+\mathrm{XXX}\)
Explanation:
: Sickleceell anaemia is a autosomal linked tecessive trait which gets transmitted from parents to offspring's when both the partners are the carrier for the gene. Carrier Mother \(\mathrm{X} \quad\) Carrier Father
NEET Test Series from KOTA - 10 Papers In MS WORD
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Principle of Inheritance and Variation
184754
In a marriage between male with blood group A and female with blood group B, the progeny had either blood group \(A B\) or \(B\). What could be the possible genotype of parents?
: Male with blood group A can have genotype \(\mathrm{I}^{\mathrm{A}} \mathrm{i}\) or \(\mathrm{I}^{\mathrm{A}} \mathrm{I}^{\mathrm{A}}\). - Female with blood group \(\mathbf{B}\) can have genotype \(I^{\mathrm{F}} I^{\mathrm{B}}\) or \(\mathrm{I}_{\mathrm{i}}\)
NEET (Odisha)-2019
Principle of Inheritance and Variation
184758
Of a normal couple, half the sons are haemophiliac while half the daughters are carriers. the gene is located on
1 X-chromosome of father
2 Y-chromosome of father
3 one X-chromosome of mother
4 both the X-chromosomes of mother APMT-1993
Explanation:
: The gene of haemophilia is located on X chromosome. In this case where half the sons are haemophilic and half the daughters are camiers, it is possible only when the gene responsible for haemophilia is located on one X-chromosome of mother.
Principle of Inheritance and Variation
184759
A colour blind mother and normal father would have
1 colour blind sons and normalicarrier daughters
2 colour blind sons and daughters
3 all colour blind
4 all normal APMT-1992
Explanation:
: A colourblind mother and normal father will have colour blind sons and normal/carrier daughters. Colour blind mother \(\times \quad\) Normal father
Principle of Inheritance and Variation
184764
Which of the following is correct match?
1 XO (i) Flat nose,
2 42 AA simian crease syndrome (ii) Webbing of \(+X Y\) neck
3 44 AA (iii) Anaemia, syndrome
4 Klinefelter's \(+\mathrm{XXX}\)
Explanation:
: Sickleceell anaemia is a autosomal linked tecessive trait which gets transmitted from parents to offspring's when both the partners are the carrier for the gene. Carrier Mother \(\mathrm{X} \quad\) Carrier Father
