NEET Test Series from KOTA - 10 Papers In MS WORD
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Principle of Inheritance and Variation
184570
A normal woman, whose father was colourblind is married to a normal man. The sons would be
1 \(75 \%\) colourblind
2 \(50 \%\) colourblind
3 all normal
4 All colourblind
Explanation:
A normal woman, whose father was colour blind is married to a normal man, the son would be \(50 \%\) colourblind. The genotype of normal man \(=X Y\).
CG PMT-2006
Principle of Inheritance and Variation
184571
If a haemophilic man marries a normal lady, the offsprings will be
1 all haemophilic
2 all normal
3 haemophilic daughters
4 haemophilic sons
Explanation:
Exp: All offspring will be normal.
CG PMT-2006
Principle of Inheritance and Variation
184579
A colourblind mother and normal father would have
1 colour blind sons and normal/carrier daughters
2 colour blind sons and daughters
3 all colour blind
4 all normal
Explanation:
A colourblind mother and normal father would have colourblind sons and normal / carrier daughter.
BVP-2012
Principle of Inheritance and Variation
184585
Which one of the following conditions of the zygotic cell would lead to the birth of a normal human female child
1 one \(\mathrm{X}\) and one \(\mathrm{Y}\) chromosome
2 two \(\mathrm{X}\) chromosomes
3 only one Y chromosome
4 only one X chromosome
Explanation:
A normal human female has two \(X\) chromosomes (XX), while males have one \(\mathrm{X}\) and one \(\mathrm{Y}\) chromosome (XY). So, two X chromosomes would lead to the birth of a normal female child.
184570
A normal woman, whose father was colourblind is married to a normal man. The sons would be
1 \(75 \%\) colourblind
2 \(50 \%\) colourblind
3 all normal
4 All colourblind
Explanation:
A normal woman, whose father was colour blind is married to a normal man, the son would be \(50 \%\) colourblind. The genotype of normal man \(=X Y\).
CG PMT-2006
Principle of Inheritance and Variation
184571
If a haemophilic man marries a normal lady, the offsprings will be
1 all haemophilic
2 all normal
3 haemophilic daughters
4 haemophilic sons
Explanation:
Exp: All offspring will be normal.
CG PMT-2006
Principle of Inheritance and Variation
184579
A colourblind mother and normal father would have
1 colour blind sons and normal/carrier daughters
2 colour blind sons and daughters
3 all colour blind
4 all normal
Explanation:
A colourblind mother and normal father would have colourblind sons and normal / carrier daughter.
BVP-2012
Principle of Inheritance and Variation
184585
Which one of the following conditions of the zygotic cell would lead to the birth of a normal human female child
1 one \(\mathrm{X}\) and one \(\mathrm{Y}\) chromosome
2 two \(\mathrm{X}\) chromosomes
3 only one Y chromosome
4 only one X chromosome
Explanation:
A normal human female has two \(X\) chromosomes (XX), while males have one \(\mathrm{X}\) and one \(\mathrm{Y}\) chromosome (XY). So, two X chromosomes would lead to the birth of a normal female child.
184570
A normal woman, whose father was colourblind is married to a normal man. The sons would be
1 \(75 \%\) colourblind
2 \(50 \%\) colourblind
3 all normal
4 All colourblind
Explanation:
A normal woman, whose father was colour blind is married to a normal man, the son would be \(50 \%\) colourblind. The genotype of normal man \(=X Y\).
CG PMT-2006
Principle of Inheritance and Variation
184571
If a haemophilic man marries a normal lady, the offsprings will be
1 all haemophilic
2 all normal
3 haemophilic daughters
4 haemophilic sons
Explanation:
Exp: All offspring will be normal.
CG PMT-2006
Principle of Inheritance and Variation
184579
A colourblind mother and normal father would have
1 colour blind sons and normal/carrier daughters
2 colour blind sons and daughters
3 all colour blind
4 all normal
Explanation:
A colourblind mother and normal father would have colourblind sons and normal / carrier daughter.
BVP-2012
Principle of Inheritance and Variation
184585
Which one of the following conditions of the zygotic cell would lead to the birth of a normal human female child
1 one \(\mathrm{X}\) and one \(\mathrm{Y}\) chromosome
2 two \(\mathrm{X}\) chromosomes
3 only one Y chromosome
4 only one X chromosome
Explanation:
A normal human female has two \(X\) chromosomes (XX), while males have one \(\mathrm{X}\) and one \(\mathrm{Y}\) chromosome (XY). So, two X chromosomes would lead to the birth of a normal female child.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Principle of Inheritance and Variation
184570
A normal woman, whose father was colourblind is married to a normal man. The sons would be
1 \(75 \%\) colourblind
2 \(50 \%\) colourblind
3 all normal
4 All colourblind
Explanation:
A normal woman, whose father was colour blind is married to a normal man, the son would be \(50 \%\) colourblind. The genotype of normal man \(=X Y\).
CG PMT-2006
Principle of Inheritance and Variation
184571
If a haemophilic man marries a normal lady, the offsprings will be
1 all haemophilic
2 all normal
3 haemophilic daughters
4 haemophilic sons
Explanation:
Exp: All offspring will be normal.
CG PMT-2006
Principle of Inheritance and Variation
184579
A colourblind mother and normal father would have
1 colour blind sons and normal/carrier daughters
2 colour blind sons and daughters
3 all colour blind
4 all normal
Explanation:
A colourblind mother and normal father would have colourblind sons and normal / carrier daughter.
BVP-2012
Principle of Inheritance and Variation
184585
Which one of the following conditions of the zygotic cell would lead to the birth of a normal human female child
1 one \(\mathrm{X}\) and one \(\mathrm{Y}\) chromosome
2 two \(\mathrm{X}\) chromosomes
3 only one Y chromosome
4 only one X chromosome
Explanation:
A normal human female has two \(X\) chromosomes (XX), while males have one \(\mathrm{X}\) and one \(\mathrm{Y}\) chromosome (XY). So, two X chromosomes would lead to the birth of a normal female child.
