237972
For assimilation of one $\mathrm{CO}_{2}$ molecule; the energy required in form of ATP \& $\mathrm{NADPH}_{2}$
1 2 ATP \& $2 \mathrm{NADPH}_{2}$
2 5 ATP \& $3 \mathrm{NADPH}_{2}$
3 3 ATP \& $2 \mathrm{NADPH}_{2}$
4 18 ATP \& $12 \mathrm{NADPH}_{2}$
Explanation:
C Photosynthesis is actually an oxidationreduction process in which water is oxidized and $\mathrm{CO}_{2}$ is reduced to carbohydrates. The reduction of $\mathrm{CO}_{2}$ to carbohydrates needs assimilatory powers i.e. ATP and $\mathrm{NADPH}_{2}$. In the calvin cycle, $\mathrm{CO}_{2}$ acceptor molecule is $\mathrm{RuBP}$ or $\mathrm{RuDP}$. The enzyme catalyzing this reaction is RuBP carboxylase/oxygenase (RuBisCO). As Calvin cycle takes in only one carbon $\left(\right.$ as $\left.\mathrm{CO}_{2}\right)$ at a time, it takes six turns of the cycle to produce a net gain of six carbons (i.e., hexose or glucose). In this cycle, for the formation of one mole of hexose sugar (glucose), 18 ATP and 12 $\mathrm{NADPH}_{2}$ are used. For 6 molecules of $\mathrm{CO}_{2}$, it needs 18 ATP and $12 \mathrm{NADPH}_{2}$ molecules. So for the assimilation of one molecule of $\mathrm{CO}_{2}$, it needs 3 ATP and $2 \mathrm{NADPH}_{2}$ molecules.
AIPMT-2000
Photosynthesis in higher plants
237973
The first step for initiation of photosynthesis will be:
1 Photolysis in water
2 Excitement of chlorophyll molecule due to absorption of light
3 ATP formation
4 Glucose formation
Explanation:
B Plant leaves contain chloroplasts, which contain red, to green pigments known as chlorophylls where photosynthesis occurs. The photon of light that the chlorophyll absorbs causes it to become excited and release electrons. Hence, the first step in photosynthesis is the excitement of an electron of chlorophyll by a photon of light.
AIPMT-2000
Photosynthesis in higher plants
237974
Total amount of energy trapped by green plants in food is called
1 Gross primary production
2 Net primary production
3 Standing crop
4 Standing state
Explanation:
A Gross primary productivity:- It is the rate of the production of organic matter during photosynthesis, showing total solar energy converted into chemical energy. So the total amount of energy trapped. - Gross primary productivity (GPP) is the rate at which solar energy is captured in sugar molecule during photosynthesis.
AIPMT-1998
Photosynthesis in higher plants
237976
A photosynthesising plant is releasing ${ }^{18} \mathrm{O}$ more than the normal. The plant must have been supplied with
1 $\mathrm{O}_{3}$
2 $\mathrm{H}_{2} \mathrm{O}$ with ${ }^{18} \mathrm{O}$
3 $\mathrm{CO}_{2}$ with ${ }^{18} \mathrm{O}$
4 $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}$ with ${ }^{18} \mathrm{O}$
Explanation:
B The water molecule breaks up into hydrogen and oxygen in the illuminated chloroplasts, which is called photolysis of water. A Photosynthesizing plant is reclosing ${ }^{18} \mathrm{O}$, more than the normal. The plant must have been supplied with ${ }^{18} \mathrm{O}$ with $\mathrm{H}_{2} \mathrm{O}$.
AIPMT-1993
Photosynthesis in higher plants
237980
Primary acceptor of $\mathrm{CO}_{2}$ in photosynthesis is:
1 Phosphoric acid
2 Rlbulose phosphate
3 Glucose
4 Ribulose 1, 5 biphosphate
Explanation:
D Ribulose - 1, 5 - biphosphate acts as $\mathrm{CO}_{2}$ acceptor and 6 moles of RuBP react with 6 moles of $\mathrm{CO}_{2}$ and 6 moles of water giving rise to 12 moles of 3phosphoglyceric acid. Ribulose - 1, 5 - biphosphate (6 moles) $+6 \mathrm{CO}_{2}+6$ $\mathrm{H}_{2} \mathrm{O} \stackrel{\text { Carboxydismutase }}{\longrightarrow} 3$ - phosphoglyceric $\operatorname{acid}(12$ moles)
237972
For assimilation of one $\mathrm{CO}_{2}$ molecule; the energy required in form of ATP \& $\mathrm{NADPH}_{2}$
1 2 ATP \& $2 \mathrm{NADPH}_{2}$
2 5 ATP \& $3 \mathrm{NADPH}_{2}$
3 3 ATP \& $2 \mathrm{NADPH}_{2}$
4 18 ATP \& $12 \mathrm{NADPH}_{2}$
Explanation:
C Photosynthesis is actually an oxidationreduction process in which water is oxidized and $\mathrm{CO}_{2}$ is reduced to carbohydrates. The reduction of $\mathrm{CO}_{2}$ to carbohydrates needs assimilatory powers i.e. ATP and $\mathrm{NADPH}_{2}$. In the calvin cycle, $\mathrm{CO}_{2}$ acceptor molecule is $\mathrm{RuBP}$ or $\mathrm{RuDP}$. The enzyme catalyzing this reaction is RuBP carboxylase/oxygenase (RuBisCO). As Calvin cycle takes in only one carbon $\left(\right.$ as $\left.\mathrm{CO}_{2}\right)$ at a time, it takes six turns of the cycle to produce a net gain of six carbons (i.e., hexose or glucose). In this cycle, for the formation of one mole of hexose sugar (glucose), 18 ATP and 12 $\mathrm{NADPH}_{2}$ are used. For 6 molecules of $\mathrm{CO}_{2}$, it needs 18 ATP and $12 \mathrm{NADPH}_{2}$ molecules. So for the assimilation of one molecule of $\mathrm{CO}_{2}$, it needs 3 ATP and $2 \mathrm{NADPH}_{2}$ molecules.
AIPMT-2000
Photosynthesis in higher plants
237973
The first step for initiation of photosynthesis will be:
1 Photolysis in water
2 Excitement of chlorophyll molecule due to absorption of light
3 ATP formation
4 Glucose formation
Explanation:
B Plant leaves contain chloroplasts, which contain red, to green pigments known as chlorophylls where photosynthesis occurs. The photon of light that the chlorophyll absorbs causes it to become excited and release electrons. Hence, the first step in photosynthesis is the excitement of an electron of chlorophyll by a photon of light.
AIPMT-2000
Photosynthesis in higher plants
237974
Total amount of energy trapped by green plants in food is called
1 Gross primary production
2 Net primary production
3 Standing crop
4 Standing state
Explanation:
A Gross primary productivity:- It is the rate of the production of organic matter during photosynthesis, showing total solar energy converted into chemical energy. So the total amount of energy trapped. - Gross primary productivity (GPP) is the rate at which solar energy is captured in sugar molecule during photosynthesis.
AIPMT-1998
Photosynthesis in higher plants
237976
A photosynthesising plant is releasing ${ }^{18} \mathrm{O}$ more than the normal. The plant must have been supplied with
1 $\mathrm{O}_{3}$
2 $\mathrm{H}_{2} \mathrm{O}$ with ${ }^{18} \mathrm{O}$
3 $\mathrm{CO}_{2}$ with ${ }^{18} \mathrm{O}$
4 $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}$ with ${ }^{18} \mathrm{O}$
Explanation:
B The water molecule breaks up into hydrogen and oxygen in the illuminated chloroplasts, which is called photolysis of water. A Photosynthesizing plant is reclosing ${ }^{18} \mathrm{O}$, more than the normal. The plant must have been supplied with ${ }^{18} \mathrm{O}$ with $\mathrm{H}_{2} \mathrm{O}$.
AIPMT-1993
Photosynthesis in higher plants
237980
Primary acceptor of $\mathrm{CO}_{2}$ in photosynthesis is:
1 Phosphoric acid
2 Rlbulose phosphate
3 Glucose
4 Ribulose 1, 5 biphosphate
Explanation:
D Ribulose - 1, 5 - biphosphate acts as $\mathrm{CO}_{2}$ acceptor and 6 moles of RuBP react with 6 moles of $\mathrm{CO}_{2}$ and 6 moles of water giving rise to 12 moles of 3phosphoglyceric acid. Ribulose - 1, 5 - biphosphate (6 moles) $+6 \mathrm{CO}_{2}+6$ $\mathrm{H}_{2} \mathrm{O} \stackrel{\text { Carboxydismutase }}{\longrightarrow} 3$ - phosphoglyceric $\operatorname{acid}(12$ moles)
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WhatsApp Here
Photosynthesis in higher plants
237972
For assimilation of one $\mathrm{CO}_{2}$ molecule; the energy required in form of ATP \& $\mathrm{NADPH}_{2}$
1 2 ATP \& $2 \mathrm{NADPH}_{2}$
2 5 ATP \& $3 \mathrm{NADPH}_{2}$
3 3 ATP \& $2 \mathrm{NADPH}_{2}$
4 18 ATP \& $12 \mathrm{NADPH}_{2}$
Explanation:
C Photosynthesis is actually an oxidationreduction process in which water is oxidized and $\mathrm{CO}_{2}$ is reduced to carbohydrates. The reduction of $\mathrm{CO}_{2}$ to carbohydrates needs assimilatory powers i.e. ATP and $\mathrm{NADPH}_{2}$. In the calvin cycle, $\mathrm{CO}_{2}$ acceptor molecule is $\mathrm{RuBP}$ or $\mathrm{RuDP}$. The enzyme catalyzing this reaction is RuBP carboxylase/oxygenase (RuBisCO). As Calvin cycle takes in only one carbon $\left(\right.$ as $\left.\mathrm{CO}_{2}\right)$ at a time, it takes six turns of the cycle to produce a net gain of six carbons (i.e., hexose or glucose). In this cycle, for the formation of one mole of hexose sugar (glucose), 18 ATP and 12 $\mathrm{NADPH}_{2}$ are used. For 6 molecules of $\mathrm{CO}_{2}$, it needs 18 ATP and $12 \mathrm{NADPH}_{2}$ molecules. So for the assimilation of one molecule of $\mathrm{CO}_{2}$, it needs 3 ATP and $2 \mathrm{NADPH}_{2}$ molecules.
AIPMT-2000
Photosynthesis in higher plants
237973
The first step for initiation of photosynthesis will be:
1 Photolysis in water
2 Excitement of chlorophyll molecule due to absorption of light
3 ATP formation
4 Glucose formation
Explanation:
B Plant leaves contain chloroplasts, which contain red, to green pigments known as chlorophylls where photosynthesis occurs. The photon of light that the chlorophyll absorbs causes it to become excited and release electrons. Hence, the first step in photosynthesis is the excitement of an electron of chlorophyll by a photon of light.
AIPMT-2000
Photosynthesis in higher plants
237974
Total amount of energy trapped by green plants in food is called
1 Gross primary production
2 Net primary production
3 Standing crop
4 Standing state
Explanation:
A Gross primary productivity:- It is the rate of the production of organic matter during photosynthesis, showing total solar energy converted into chemical energy. So the total amount of energy trapped. - Gross primary productivity (GPP) is the rate at which solar energy is captured in sugar molecule during photosynthesis.
AIPMT-1998
Photosynthesis in higher plants
237976
A photosynthesising plant is releasing ${ }^{18} \mathrm{O}$ more than the normal. The plant must have been supplied with
1 $\mathrm{O}_{3}$
2 $\mathrm{H}_{2} \mathrm{O}$ with ${ }^{18} \mathrm{O}$
3 $\mathrm{CO}_{2}$ with ${ }^{18} \mathrm{O}$
4 $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}$ with ${ }^{18} \mathrm{O}$
Explanation:
B The water molecule breaks up into hydrogen and oxygen in the illuminated chloroplasts, which is called photolysis of water. A Photosynthesizing plant is reclosing ${ }^{18} \mathrm{O}$, more than the normal. The plant must have been supplied with ${ }^{18} \mathrm{O}$ with $\mathrm{H}_{2} \mathrm{O}$.
AIPMT-1993
Photosynthesis in higher plants
237980
Primary acceptor of $\mathrm{CO}_{2}$ in photosynthesis is:
1 Phosphoric acid
2 Rlbulose phosphate
3 Glucose
4 Ribulose 1, 5 biphosphate
Explanation:
D Ribulose - 1, 5 - biphosphate acts as $\mathrm{CO}_{2}$ acceptor and 6 moles of RuBP react with 6 moles of $\mathrm{CO}_{2}$ and 6 moles of water giving rise to 12 moles of 3phosphoglyceric acid. Ribulose - 1, 5 - biphosphate (6 moles) $+6 \mathrm{CO}_{2}+6$ $\mathrm{H}_{2} \mathrm{O} \stackrel{\text { Carboxydismutase }}{\longrightarrow} 3$ - phosphoglyceric $\operatorname{acid}(12$ moles)
237972
For assimilation of one $\mathrm{CO}_{2}$ molecule; the energy required in form of ATP \& $\mathrm{NADPH}_{2}$
1 2 ATP \& $2 \mathrm{NADPH}_{2}$
2 5 ATP \& $3 \mathrm{NADPH}_{2}$
3 3 ATP \& $2 \mathrm{NADPH}_{2}$
4 18 ATP \& $12 \mathrm{NADPH}_{2}$
Explanation:
C Photosynthesis is actually an oxidationreduction process in which water is oxidized and $\mathrm{CO}_{2}$ is reduced to carbohydrates. The reduction of $\mathrm{CO}_{2}$ to carbohydrates needs assimilatory powers i.e. ATP and $\mathrm{NADPH}_{2}$. In the calvin cycle, $\mathrm{CO}_{2}$ acceptor molecule is $\mathrm{RuBP}$ or $\mathrm{RuDP}$. The enzyme catalyzing this reaction is RuBP carboxylase/oxygenase (RuBisCO). As Calvin cycle takes in only one carbon $\left(\right.$ as $\left.\mathrm{CO}_{2}\right)$ at a time, it takes six turns of the cycle to produce a net gain of six carbons (i.e., hexose or glucose). In this cycle, for the formation of one mole of hexose sugar (glucose), 18 ATP and 12 $\mathrm{NADPH}_{2}$ are used. For 6 molecules of $\mathrm{CO}_{2}$, it needs 18 ATP and $12 \mathrm{NADPH}_{2}$ molecules. So for the assimilation of one molecule of $\mathrm{CO}_{2}$, it needs 3 ATP and $2 \mathrm{NADPH}_{2}$ molecules.
AIPMT-2000
Photosynthesis in higher plants
237973
The first step for initiation of photosynthesis will be:
1 Photolysis in water
2 Excitement of chlorophyll molecule due to absorption of light
3 ATP formation
4 Glucose formation
Explanation:
B Plant leaves contain chloroplasts, which contain red, to green pigments known as chlorophylls where photosynthesis occurs. The photon of light that the chlorophyll absorbs causes it to become excited and release electrons. Hence, the first step in photosynthesis is the excitement of an electron of chlorophyll by a photon of light.
AIPMT-2000
Photosynthesis in higher plants
237974
Total amount of energy trapped by green plants in food is called
1 Gross primary production
2 Net primary production
3 Standing crop
4 Standing state
Explanation:
A Gross primary productivity:- It is the rate of the production of organic matter during photosynthesis, showing total solar energy converted into chemical energy. So the total amount of energy trapped. - Gross primary productivity (GPP) is the rate at which solar energy is captured in sugar molecule during photosynthesis.
AIPMT-1998
Photosynthesis in higher plants
237976
A photosynthesising plant is releasing ${ }^{18} \mathrm{O}$ more than the normal. The plant must have been supplied with
1 $\mathrm{O}_{3}$
2 $\mathrm{H}_{2} \mathrm{O}$ with ${ }^{18} \mathrm{O}$
3 $\mathrm{CO}_{2}$ with ${ }^{18} \mathrm{O}$
4 $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}$ with ${ }^{18} \mathrm{O}$
Explanation:
B The water molecule breaks up into hydrogen and oxygen in the illuminated chloroplasts, which is called photolysis of water. A Photosynthesizing plant is reclosing ${ }^{18} \mathrm{O}$, more than the normal. The plant must have been supplied with ${ }^{18} \mathrm{O}$ with $\mathrm{H}_{2} \mathrm{O}$.
AIPMT-1993
Photosynthesis in higher plants
237980
Primary acceptor of $\mathrm{CO}_{2}$ in photosynthesis is:
1 Phosphoric acid
2 Rlbulose phosphate
3 Glucose
4 Ribulose 1, 5 biphosphate
Explanation:
D Ribulose - 1, 5 - biphosphate acts as $\mathrm{CO}_{2}$ acceptor and 6 moles of RuBP react with 6 moles of $\mathrm{CO}_{2}$ and 6 moles of water giving rise to 12 moles of 3phosphoglyceric acid. Ribulose - 1, 5 - biphosphate (6 moles) $+6 \mathrm{CO}_{2}+6$ $\mathrm{H}_{2} \mathrm{O} \stackrel{\text { Carboxydismutase }}{\longrightarrow} 3$ - phosphoglyceric $\operatorname{acid}(12$ moles)
237972
For assimilation of one $\mathrm{CO}_{2}$ molecule; the energy required in form of ATP \& $\mathrm{NADPH}_{2}$
1 2 ATP \& $2 \mathrm{NADPH}_{2}$
2 5 ATP \& $3 \mathrm{NADPH}_{2}$
3 3 ATP \& $2 \mathrm{NADPH}_{2}$
4 18 ATP \& $12 \mathrm{NADPH}_{2}$
Explanation:
C Photosynthesis is actually an oxidationreduction process in which water is oxidized and $\mathrm{CO}_{2}$ is reduced to carbohydrates. The reduction of $\mathrm{CO}_{2}$ to carbohydrates needs assimilatory powers i.e. ATP and $\mathrm{NADPH}_{2}$. In the calvin cycle, $\mathrm{CO}_{2}$ acceptor molecule is $\mathrm{RuBP}$ or $\mathrm{RuDP}$. The enzyme catalyzing this reaction is RuBP carboxylase/oxygenase (RuBisCO). As Calvin cycle takes in only one carbon $\left(\right.$ as $\left.\mathrm{CO}_{2}\right)$ at a time, it takes six turns of the cycle to produce a net gain of six carbons (i.e., hexose or glucose). In this cycle, for the formation of one mole of hexose sugar (glucose), 18 ATP and 12 $\mathrm{NADPH}_{2}$ are used. For 6 molecules of $\mathrm{CO}_{2}$, it needs 18 ATP and $12 \mathrm{NADPH}_{2}$ molecules. So for the assimilation of one molecule of $\mathrm{CO}_{2}$, it needs 3 ATP and $2 \mathrm{NADPH}_{2}$ molecules.
AIPMT-2000
Photosynthesis in higher plants
237973
The first step for initiation of photosynthesis will be:
1 Photolysis in water
2 Excitement of chlorophyll molecule due to absorption of light
3 ATP formation
4 Glucose formation
Explanation:
B Plant leaves contain chloroplasts, which contain red, to green pigments known as chlorophylls where photosynthesis occurs. The photon of light that the chlorophyll absorbs causes it to become excited and release electrons. Hence, the first step in photosynthesis is the excitement of an electron of chlorophyll by a photon of light.
AIPMT-2000
Photosynthesis in higher plants
237974
Total amount of energy trapped by green plants in food is called
1 Gross primary production
2 Net primary production
3 Standing crop
4 Standing state
Explanation:
A Gross primary productivity:- It is the rate of the production of organic matter during photosynthesis, showing total solar energy converted into chemical energy. So the total amount of energy trapped. - Gross primary productivity (GPP) is the rate at which solar energy is captured in sugar molecule during photosynthesis.
AIPMT-1998
Photosynthesis in higher plants
237976
A photosynthesising plant is releasing ${ }^{18} \mathrm{O}$ more than the normal. The plant must have been supplied with
1 $\mathrm{O}_{3}$
2 $\mathrm{H}_{2} \mathrm{O}$ with ${ }^{18} \mathrm{O}$
3 $\mathrm{CO}_{2}$ with ${ }^{18} \mathrm{O}$
4 $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}$ with ${ }^{18} \mathrm{O}$
Explanation:
B The water molecule breaks up into hydrogen and oxygen in the illuminated chloroplasts, which is called photolysis of water. A Photosynthesizing plant is reclosing ${ }^{18} \mathrm{O}$, more than the normal. The plant must have been supplied with ${ }^{18} \mathrm{O}$ with $\mathrm{H}_{2} \mathrm{O}$.
AIPMT-1993
Photosynthesis in higher plants
237980
Primary acceptor of $\mathrm{CO}_{2}$ in photosynthesis is:
1 Phosphoric acid
2 Rlbulose phosphate
3 Glucose
4 Ribulose 1, 5 biphosphate
Explanation:
D Ribulose - 1, 5 - biphosphate acts as $\mathrm{CO}_{2}$ acceptor and 6 moles of RuBP react with 6 moles of $\mathrm{CO}_{2}$ and 6 moles of water giving rise to 12 moles of 3phosphoglyceric acid. Ribulose - 1, 5 - biphosphate (6 moles) $+6 \mathrm{CO}_{2}+6$ $\mathrm{H}_{2} \mathrm{O} \stackrel{\text { Carboxydismutase }}{\longrightarrow} 3$ - phosphoglyceric $\operatorname{acid}(12$ moles)